<h1>1</h1>
<p><a href="http://i.imgur.com/0Q596.jpg%5B/url%5D">http://i.imgur.com/0Q596.jpg</a></p>
<h1>2</h1>
<p><a href="http://i.imgur.com/PPqxr.jpg%5B/url%5D">http://i.imgur.com/PPqxr.jpg</a></p>
<h1>3</h1>
<p><a href="http://i.imgur.com/ppzC3.jpg%5B/url%5D">http://i.imgur.com/ppzC3.jpg</a></p>
<h1>4</h1>
<p><a href="http://i.imgur.com/sDcsm.jpg%5B/url%5D">http://i.imgur.com/sDcsm.jpg</a></p>
<p>1.Solving the system, a=-2/5 b=11/5
Thus, the answer is E
2. (x+y)/x=x/x+y/x=1+r
E
3. It’s a right Triangle, so the leg is 6
B
4. Each half triangle is a 5-12-13 right triangle, so the perimeter is 26+10=36
C</p>
<h1>2 is also perfect for making up numbers. Pick an x value and a y value, calculate what they ask for and then stick the r value back into the answer choices…</h1>
<h1>3 is NOT 6. The big triangle is not a right triangle. You have to do the pythag theorem twice. On the left triangle, you will get that the bottom piece is 2. 7- 2 = 5 for the right triangle’s bottom piece. Then, pythag thm again — E</h1>
<p>1 is E, as someone pointed out above.</p>
<p>2 is D. (x+y)/x can be rewritten as 1+y/x, which is 1+1/r, which can be rewritten as (r+1)/r.</p>
<p>3 is E, as someone pointed out above.</p>
<p>4 is C. If we label point A as the point where the altitude touches PR, we see that the altitude is also a perpendicular bisector. Since AQR is a right triangle, we use the Pythagorean Theorem to find that AR is 5. Since AR is half of PR, PR is 10. 10+13+13=36.</p>
<ol>
<li>y = 2x + 3 and y = 1-3x
a = x
b = y</li>
</ol>
<p>b = 2a + 3 and b = 1 - 3a
2a + 3 = 1 - 3a
5a = -2
a = -2/5</p>
<p>b = 2a + 3
b = 2(-2/5) + 3
b = 11/5</p>
<p>E) a = 4 - 2b
-2/5 = 4 - 2(11/5)
-2/5 = 20/5 - 22/5
-2/5 = -2/5</p>
<p>Once you have found a = -2/5 & b = 11/5 you are looking at the answer choices your eyes should immediately gravitate towards answer choice E since it is the only one that will yield a negative number.</p>
<ol>
<li> Just plug numbers in!</li>
</ol>
<p>0 < x < y
Let x = 2
Let y = 4</p>
<p>x/y = r
2/4 = 1/2
r = 1/2</p>
<p>x + y/x
2 + 4/2 = 6/2 = 3 </p>
<p>3 = r + 1/ r
3 = 1.5/0.5
3 = 3</p>
<p>Answer = D.</p>
<ol>
<li> You must first tackle triangle ABD before you can tackle triangle BCD.</li>
</ol>
<p>You have sides sqrt13 and 3. Since it is a 90 degree triangle you can do Pythagorean Identity = a^2 + b^2 = c^2
a = 3
b = x
c = sqrt13</p>
<p>9 + x^2 = 13
x^2 = 4
x = 2</p>
<p>Subtract 7 -2 = 5.
a^2 + b^2 = c^2
a = 3
b = 5
c = x</p>
<p>9 + 25 = x^2
34 = x^2
Answer = sqrt of 34 aka Answer choice E.</p>
