<p>Title says it. A guy recommended around 4, but I do not want to end up applying to 15 colleges...</p>
<p>2 , an academic safety and a financial safety.
They have to be schools that you will feel comfortable enrolling at in a worst case scenario.</p>
<p>Depends on the amount of school’s you plan on applying to.</p>
<p>If its 6 then 2 safety, 2 match, 2 reach.
I don’t know your situation but im planning on doing something like this:
- High Reach, 2. Reach, 3. Hard Match, 4. Hard Match, 5. Match, 6. Safety, 7. Safety, 8. Financial Safety</p>
<p>I only had one. It was a financial and academic safety and I would have been perfectly happy going there. As long as you love it in its own way, one is enough. Two if you want peace of mind.</p>
<p>And obviously, when I say you only need one, I’m talking about a SUPER safety. Not just like, you’re in the 75th %ile. You need to be beyond positive.</p>
<p>Depends on how “safe” it is. I had automatic admit to UC Davis through ELC so that was my safety, and I only needed one–then again, I was 100% gonna be admitted. I don’t really think you need more than two, as long as they’re truly safe. Basically, do whatever makes you feel the most comfortable.</p>
<p>It might also be a good idea to apply to a school that has rolling admissions, so you can know early on in the process that at least you’re going somewhere.</p>
<p>The thing is the Cal Poly Pomona is the only “safety” I can think of that I would have the dignity of going to. I would not even consider any other Cal States other than SLO, but that is one of my “target” schools. </p>
<p>Double Major in Comp Sci and Elect Engineering and will take several theoretical physics classes (not necessarily minor in it)
I don’t want to apply to UCs, unless some one can convince me with hard evidence that I would like it there, then I am not even bothering. </p>
<p>So My List:
Caltech
MIT
Harvey Mudd
Stanford
Carnegie Mellon
Worcester Polytechnic
Stevens Institute of Tech
Illinois Institute of Tech
Georgia Tech
Cal Poly SLO
Cal Poly Pomona</p>