<p>Well, by the time I graduate I would have taken 13-14 AP tests and 3 college courses (2 of them during the summer and Multivariable Calc during senior year).</p>
<p>So would I be able to skip a year at Berkeley? If so, how would it work?</p>
<p>There is no official process. Look at the required courses you have to take. If you're in EECS, I can help you come up with a 3-year plan. It should be quite easy to do if you plan ahead.</p>
<p>Lol, I am actually planning to major in EECS (with CE emphasis). But I won't need to make one for a while.</p>
<p>If you have a 3-year plan already, then I'd love to see yours if it's not too much trouble. If it'll take more than a couple minutes, it's ok.</p>
<p>It's just that if I can graudate from undergrad in 3 years at Berkeley, I'd choose Berkeley over Princeton and maybe even Stanford.</p>
<p>
[quote]
It's just that if I can graudate from undergrad in 3 years at Berkeley, I'd choose Berkeley over Princeton and maybe even Stanford.
[/quote]
</p>
<p>May you get the choice. Best of luck.</p>
<p>I'm kind of curious about this also. If you have AP bio credit but take the intro. bio course again in college, do you get to still use the AP bio credit as credit towards graduation (as in towards the minimum number of credits u need to graduate?) and the intro bio course credit. Kus that would be like duplicating credits wouldn't it?</p>
<p>Berkeley has a five-year BS/MS program in the works. If you can maintain a 3.5+ GPA by the time you fulfill your degree requirements, you may want to consider applying.</p>
<p>Anyway, here's a sample EECS schedule in two years. I assume you have AP credits for English, Am hist, phys, CS, calculus, and chem. The upper-division courses are some of the more popular ones people choose to take.</p>
<p>Math 53 - Multivar Calc
Phys 7B - Phys E&M
CS 61A - Program Str</p>
<h2>English 1B - Reading & Comp (grad req.)</h2>
<p>Math 54 - Lin Alg & Diff Eqns
CS 61C - Machine Str
EE 20 - Signals & Systems</p>
<h2>EE 40 - Microelectronic Circuits</h2>
<p>Math 55/CS 70 - Discrete Math, Prob & Stats
EE 105 - Microelectronics Uoper-div
CS 184 - Graphics</p>
<h2>Hum/AC - (grad req.)</h2>
<p>EE 141 - Digital Integrated Circuits.
CS 186 - Databases
CS 162 - OS
E 190 - Tech comm (grad req.)</p>
<p>
[quote]
It's just that if I can graudate from undergrad in 3 years at Berkeley, I'd choose Berkeley over Princeton and maybe even Stanford.
[/quote]
</p>
<p>While it is true that Princeton does not accept AP credits, Stanford does. Hence, if you have enough credits to graduate in 3 years from Berkeley, then you probably have enough credits to graduate in 3 years from Stanford.</p>
<p>
[quote]
Berkeley has a five-year BS/MS program in the works.
[/quote]
</p>
<p>I think it's no longer in the works, but rather it is all worked out now.</p>
<p><a href="http://www.eecs.berkeley.edu/FiveYearMS/%5B/url%5D">http://www.eecs.berkeley.edu/FiveYearMS/</a></p>
<p>However, I would point out that Stanford also offers the same thing through their so-called "coterminal" program.</p>
<p><a href="http://cs.stanford.edu/GraduateAdmissions/coterm.php%5B/url%5D">http://cs.stanford.edu/GraduateAdmissions/coterm.php</a>
<a href="http://www-ee.stanford.edu/undergrad_faq.php#Coterm%5B/url%5D">http://www-ee.stanford.edu/undergrad_faq.php#Coterm</a></p>
<p>Does Berkeley have a 5 yr program for chemical engineering?</p>
<p>How many Hum/AC classes are needed?</p>
<p>In another thread, someone said 6 classes?!?! 6 units right?!</p>
<p>Six classes, two of which you can place out of with AP tests.</p>
<p>I can't place out of more? Taking 2 AP tests for English, 2 for History, 2 for Micro/Macro Econ, 1 for Spanish, and I'd have college credit for Spanish 102.</p>
<p>No, two is the maximum. Straight from the engineering handbook (<a href="http://coe.berkeley.edu/current_students/advising06-07.pdf):%5B/url%5D">http://coe.berkeley.edu/current_students/advising06-07.pdf):</a></p>
<ol>
<li>No more than two of the six H/SS courses can be satisfied by AP, IB or A-Levels credit.</li>
</ol>
<p>^Thanks for the clarification. :)</p>