<p>A machine has three small windows, each of which displays a single digit number. The machine is rigged so that in each window, the digits appear in the following consistent and repeating pattern: 3,7,9,2,5. The machine currently displays the following three digits: 7,2,3. What will be the sum of the digits on the next display?</p>
<p>A) 8
B) 12
C) 21
D) 26
E) 957</p>
<p>7, 2, 3</p>
<p>means that the next three digits will be</p>
<p>9, 5, 7</p>
<p>9 + 5 + 7 = 21, C</p>
<p>Um…isn’t it C)21? If the first window shows a 7, the next number in it will be a 9. If the second window shows a 2, the next number in it will be a 5. If the third window shows a 3, the next number in it will be a 7. </p>
<p>9+5+7=21</p>
<p>That’s my interpretation of it…it is a weirdly worded problem, though.</p>
<p>EDIT: Jamesford beat me to it…i guess that’s right, then.</p>
<p>it’s C. </p>
<p>A, B, and E make no sense. D is not possible because even the highest 3 numbers of the five digits dont add up to 26. A is wrong for the same reason; even the lowest numbers dont add up to 8.</p>
<p>:)</p>
<p>weird never had a queston like that… i dont like the wording</p>
<p>Actually, if you were REALLY stumped on this question, although I wouldn’t recommend this method, you could use process of elimination.</p>
<p>A is impossible because the smallest numbers add up to a number greater than 8
D and E are impossible because 957 and 26 are larger than the sum of the largest three numbers (although I like how they try to trick you with 957 lol)</p>
<p>So we’re left with B and C</p>
<p>B is ■■■■■■■■ because it requires that the three numbers are 7, 3 and 2 AGAIN. Which is impossible.</p>
<p>So the answer is C</p>
<p>Only use these kind of POE methods if you’ve got lots of time to do it.</p>
<p>^Or, if you are really bold, you’d figure that the 957 answer is only there to trick test takers (common on the SAT), so it would make sense that the next three numbers are 9, 5, and 7.</p>