<p>They can be cracked by making your own simple #s instead of 70s-100s. What about 2–> 4? Let’s see, we have 2, 3, and 4. That’s three #s, and you can get three by subtracting 2 from 4 and add one. That’s what the guy above me had, but the point is to think of easier #s to get a common formula before going to the hard one. If the sum of #s from -25 to x is 72, how many integers are there? Hard, right? Well sorry this isn’t the best example I could find, but take a # like -2 and the sum is 3. Well -2±1+0+1+2+3=====3, we had 6 integers. Now again this isn’t the best example but you can try to see patterns and such. In that previous problem, we know that to get to +25, you have to go through what, 51 integers(correct me if I’m wrong)? Then you just add and I don’t think it adds up to 72 but you get the idea.</p>