<p>explode-I remember that, I got 1/256 too.</p>
<p>X/\ 2 + XY</p>
<p>you factor out the X, and it turns out that both number have to be odd, so I and III</p>
<p>im 110% sure the answer was I & III (x+y is odd and x is odd)</p>
<p>so it was one number had to be odd and the sum? i think i got it then.</p>
<p>Yeah i got that ^ .... i hope/think.</p>
<p>roflmao, i cant believe that CCers are neurotic enough to just simply keep on going after an entire 10+-page thread was deleted like this.</p>
<p>Ned, anybody? for the bar graph</p>
<p>and anyway, i got this wrong, but why was it C and not B? I was rushing and didn't read the Q closely. what did it ask, and what were the choices, if anybody remembers</p>
<p>Yea I got Ned</p>
<p>I got 3 for the (6n+1)(3n-11) one though, maybe I'm wrong on that one.</p>
<p>For the 4 circles and the circle in the middle, was it sqrt 2 - 1/2?</p>
<p>@meili: You sure? Some people are saying X<0 and stuff. I chose x+y is odd and x is odd.</p>
<p>yea I think I got that meili</p>
<p>and yeah i think i got what you got prothero.</p>
<p>and Ibanez, I chose what you chose too. that's why i was confused earlier about the x<0 and y<0 stuff, i guess.</p>
<p>wait is 0 an integer</p>
<p>wait wasn't the question with the x<0 and y<0 a completely different question??</p>
<p>wait i dunno lol</p>
<p>yeah the question with the x and y was: x+y<x-y</p>
<p>I got y had to be less than 0.</p>
<p>yea..im pretty sure it was like...y+x<y-x..or something....which one of these has to be true..and the answer was x has to be less then zero</p>
<p>^ nuggetsfan,</p>
<p>the x<0 and y<0... i THINK this is what they're talking about:</p>
<p>the question was
x + y < x - y</p>
<p>so what MUST be true? (i think)</p>
<p>is it
x<0
or
y<0.</p>
<p>the thing is, i dont think i could have remebered that question wrong because if the signs were flipped (i.e. x+y > x-y), that isn't even really a question lol</p>
<p>and in that case, it's y<0, choice (E).</p>
<p>ok...i just mixed the letters up...lol..but..that was it</p>
<p>the letter ur subtracting on the right side of the inequality..had to be greater...whether it was x or y..i forgot</p>
<p>yeah which ever one had the minus sign before it i put had to be less than zero. ther was one with x raised to the two thirds=y and then x^4 is y to what power. i think i got 8/3. anyone?</p>
<p>^ y is to what power---> 6</p>
<p>Yeah it was 6. I just substituted x with 8 and used a fractional exponent trick to rewrite it with a cube root square, which my Math B teacher taught me.</p>