<p>if u chose a number higher than 9 it wouldn’t have worked</p>
<p>could 155 work for the 3-digit number grid-in question???</p>
<p>i dunno if it said no repeat numbers or not</p>
<p>Yes it could. Also, I used 425.</p>
<p>And HEY, what about my raw score of 53? :D</p>
<p>Edit: whoops sorry, no. It did say different!</p>
<p>you should see “d” sign on your calculator or on catalog. And it goes like this for example:</p>
<p>d(3x^2 + 4x , x)</p>
<p>then you should get the derivative.</p>
<ul>
<li>dychang</li>
</ul>
<p>Unfortunately no, one of the requirements was that each digit was a different integer factor of 40. No repeats. Sorry.</p>
<p>Acceptable answers were 245, 425, 821, 281 (maybe more)</p>
<p>could 155 work for the 3-digit number grid-in question???</p>
<p>Each number had to be unique. Was stated.</p>
<p>I think it said that the integer was made up three different factors of 40.
.</p>
<p>hm… I don’t remember seeing that … darn…</p>
<p>but didn’t it say odd integer"s" ? for the digits?</p>
<p>What was the dice answer?</p>
<ul>
<li>dychang</li>
</ul>
<p>It is impossible to make an odd three digit number that has three different odd integers of which all are a factor of 40.</p>
<p>I think you mixed something up. The three digit number be odd, not each individual digit.</p>
<ul>
<li>Prep 8</li>
</ul>
<p>The dice answer was the circle, no other set up is possible.</p>
<p>re: that integer problem
the conditions were
- number is odd
- each digit is a DIFFERENT factor of 40
- digits added up to 11</p>
<p>I put 245 myself.</p>
<p>um. for the line and the circle question, i remember they said that the line was (y^2) = 25 - (x^2). so u no that when x = 0, y = 5. that means one point on the line was (0,5). then i used that 3-4-5 triangle and got another point, (-4,3)
then i used slope formula (5-3) / [0-(-4)] and i got 2/4 = 1/2.</p>
<p>Alright, I’ll take my own shot at the curve, guys.</p>
<p>54=800 (I know this is true! 
)
53=780
52=760
51=740
50=720
49=710
48=700
47=690
46=680
45=670
ETC</p>
<p>Crzanzboi - I did the same thing!
And everyone else said its wrong.
so IDK, but hopefully it isn’t.
lol.</p>
<ul>
<li>crzazniboi </li>
</ul>
<p>any equation in the form of ax^2+by^2=r^2 is NOT an equation of a line (which is mx+b). In this case, this is the equation of a circle. (0, 5) is not a point on the line, it is a point on the circle, here are two ways to properly calculate the correct answer.</p>
<p>
</p>
<ul>
<li>future</li>
</ul>
<p>On December’s SAT a 52=750. However, this one seemed harder. Due to stupid time/mistakes, I know I did not do better =/. Let us hope the curve is a little more forgiving this time around.</p>
<p>And I ran out of time and eyeballed the slope one, putting down 5/4. Lets hope I’m right and get my 800…</p>
<p>
</p>
<p>x^2 + y^2 = 25 was referring to the circle, not the line…so (0,5) wasn’t a point on the line</p>
<p>that was the equation of the cirlce not the line </p>
<p>and the problem has already been proved with differentiation its 4/3</p>