<p>i think that is great reasoning LOL</p>
<p>Astronauts were weighed down by their heavy space suits. Apollo-era space suits weighed 180 pounds (on Earth).</p>
<p>If anyone remembers the exact question, I may be able to tell you if the answer is 2.5 or 6.</p>
<p>The blue book scale was 59/75 for a 800. since this was harder, could it be possible that 57/58 is 800 :D?</p>
<p>how much farther are you able to throw an object on the moon than th earth if moon gravity = g/6</p>
<p>Yeah, its 6 times. This is because the new g is g/6. So,</p>
<p>v<em>f^2 = v</em>0^2 -2(g/6)h
v<em>0^2 = (g/3)h
h = (3v</em>0^2)/g</p>
<p>Compare with:</p>
<p>v<em>f^2 = v</em>0^2 -2(g)h
v<em>0^2 = 2gh
h = v</em>0^2/(2g).</p>
<p>Its six times more.</p>
<p>ooooooh thats what i put!!! ^^</p>
<p>How did everyone do on the last ones?</p>
<p>Yes, 6 is correct. Where did 2.5 come from, just a guess?</p>
<p>how about the rocket question?
I choese D: throw a stone (or something) to make the boat move.</p>
<p>BTW, for the mass on a string one, it was a stopwatch right?</p>
<p>Because T = 2pi sqrt(L/g) and is independent of the angle, so disturbing the system to any angle would produce the same period. From there L can be calculated.</p>
<p>That's what my reasoning was.</p>
<p>EDIT: For the rocket problem, i said moving in the boat back and forth. This is because I recalled that the way rocket are able to move in space (no atmosphere) is by pushing the rocket fuel out of the exhaust which pushes the rocket ahead. So in essense, all "motion" is internal.</p>
<p>baddddddddddddd</p>
<p>the speed of the truck that had 500 kgs dropped on it was 16m/s
the scuba diver sees the bird above its actual position
the light rays emerging from the water make a large angle to the normal?
the normal and the incident/reflected rays are on the same plane?
the positron has the highest chrage to mass ratio - I got it wrong
the alpha particle absorbs to 2 electrons
at the instance of the wave, point B is moving to the top of the page
no light exits from the vertically and horizontally arranged polarizers?</p>
<p>The graph where the force is in a opposite direction to motion and the smallest acceleration were the same
the astronaut can jump upto 6 times his usual height
the height of the tree in the image is 0.025m?
The relative motion of the plane was northwest
The voltage to each resistor was 3V
the distance from the wire where the B field is zero is 2L - I got that one wrong
The wire's B field is the circles?
The greatest EMI induced was in option D - the one at the top of the circle.
To increase frequency, k must be bigger
Capcitors store charge?
Horizontal straight line for the E-field between paralel plates?
A stpwatch is needed to find the length of the pendulum
The frictional force was 10N
Th vertical component of the force on the vaccuum cleaner was Fsin60 and the horizontal was Fcos60.
All waves (light, radio and sound) under go diffraction
Interference is responisble for the Newton's rings
The highest E-field is the option with the chrages of -2q and 2 q with q and -q.
The final momentum has a smaller magnitude
If gravitational ceased, the satelite would move tangentially
The equation x = x0 + ut + 0.5at^2 is for a frictionless incline
vertical vloecity vs time is linear
horizontal vs time is straight line (horizontal)
i'm pretty sure they asked for a proton's direction of motion in a E-field. It was parabolic upwards.
the centipetal acceleration was F/m</p>
<p>That's all I remember. I very sure of the one's that don't have a question mark. I hope this helps.</p>
<p>I put down stopwatch and erased that :(</p>
<p>I think I bombed. I didn't get half the optics. :/</p>
<p>Didn't help that I panicked and lost all arithmetic abilites. :'(</p>
<p>what rocket question?</p>
<p>^agreed with them all!!!!!!!!</p>
<p>Umm...I disagree with this:
The highest E-field is the option with the chrages of -2q and 2 q with q and -q.</p>
<p>For this one:
"The greatest EMI induced was in option D - the one at the top of the circle." I was about to choose that but finally decided to omit.
What's the reason for that? just because v is perpendicular to B? but why is the EMF the biggest?</p>
<p>mad harddd lol</p>
<p>Could someone explain why "The equation x = x0 + ut + 0.5at^2 is for a frictionless incline" is correct?
I agree with everything else except the highest electric field, for which I put all 2q magnitudes (like wavvy). </p>
<p>and which one was this: "Interference is responisble for the Newton's rings"</p>
<p>wewet234:
That equation only applies to uniformly accelerated linear motion (whatever that motion is called...I mean a thing moving in a traight line where a = constant)
For a block slipping down an incline, it's netforce is paralell to the incline, and you can get it's x and y component (x points a horizontal direction, which represents the position in the equation, y points down). Since a = F/m, F is a constant, and thus a is a constant, and thus the x component of a is constant.</p>