<p>I'm looking for - well, I don't want to jinx it - a very good score on the June 2012 SAT. With that said, I would feel good if we June takers made a thread to share some tough questions in preparation for the exam. I'll start.</p>
<p>Math:
[Grid in] At time t=0, a ball was thrown upward from an initial height of 6 feet. Until the ball hit the ground, its height, in feet, after t seconds was given by the function of h below, in which c and d are positive constants. If the ball reached its maximum height of 106 ft at t = 2.5, what was the height, in feet, of the ball at time t = 1?</p>
<p>h(t) = c-(d-4t)</p>
<p>Writing:
The price of gold has been influenced by continued inflation and [because people have lost faith] in the dollar.
(A) because people have lost faith
(B) because of the loss of faith
(C) by people which have lost faith
(D) losing faith
(E) loss of faith</p>
<p>CR is a bit tricker but feel free to ask about specific questions anyway.</p>
<p>Tried doing the first one for 10-15 mins and was finding it impossible. Then I decided to google it, and found out that the actual equation is h(t) = c- (d-4t)^2.
It was pretty simple after that.
Since you know the height at t=0, you can use that to find c and d.</p>
<p>H(0)= c - (d-4(0))^2
6= c-d^2</p>
<p>Now use that to find the actual value of c + d by plugging in t=2.5
H(2.5) = c-(d-4t)^2 Foil it out
106= c-(d^2-8dt+16t^2)
106= c-d^2+8dt-16(2.5)^2 We know that c-d^2 = 6, so sub that in
106= 6+8(2.5)d-100
200= 20d
d=10</p>
<p>Now lets use that previous c-d^2=6 to find out the value of c.</p>
<p>c-(10)^2=6
c= 106</p>
<p>Now you can just plug in the values to find the height at t=1, which is 70.</p>
<p>For the 2nd question, I want to say E, but I will go with B.</p>
<p>‘Which’ cannot be used to refer to people. I’ve actually seen a Identifying Sentence Errors problem from a BB practice test in which the error was that a person was referred to as ‘which’ instead of ‘who’.</p>
<p>As for the math problem, I don’t think that would appear on an actual test, not because it’s hard (it’s actually very straightforward) but because it’s time consuming. Nevertheless, I will try to create some problems off the top of my head and contribute to this thread.</p>
<p>Math (medium probably):
A line crosses the y-intercept when y=3 and goes through the point (2,7). What is the equation of the line perpendicular to that line?</p>
<p>Writing:
Reminiscing about the (much simpler past) as the sun tucked away under the horizon, (the night) seemed to creep up on us because (we had lost) track of time while sharing stories of our (lives). No error</p>
<p>CR:
Her ________ behavior was unusual because she had always been a ________ member in the past</p>
<p>The math question:
The line would pass through the points (0,3) and (2,7). Therefore, its slope will be 4/2 or 2. The line perpendicular to it would have a slope of -1/2. y = -1/2x + C</p>
<p>The writing question:
Misplaced modifier. “The night” cannot reminisce. B.</p>
<p>The reading question:
I was unsure what acquisitive and demure mean, though based on connotation, I would guess the answer is demure; gregarious. E.</p>
<p>These were great questions. Kudos for making them up yourself. By the way, kill, you got 2400 right? Anyway, I’ll post more questions as I run into them. :] I’ll keep the “which” thing in mind too.</p>
<p>Do you guys know how to do the problems that are like " bob works this long, Mary works this, if they work together how long will it be? I always get this wrong ( I know they’re easy) it would be nice if someone could tell me how to do those problems</p>
<p>Bob paints a wall in seven hours, Joe paints the same wall in ten. How many hours does it take Bob and Joe to paint the wall together.</p>
<p>Bob paints 1/7 of the wall per hour. Joe paints 1/10 of the wall per hour.
Together they paint (1/7)+(1/10) = 17/70 of the wall per hour. So it would take them 4.11764706 to paint the wall together.</p>
<p>Hah, 2400? Not even close. But I’m glad you found my questions helpful. More questions:</p>
<p>Math (this one might be too hard to appear on an actual test):
A bag of 10 marbles contains 3 red marbles and 7 non-red marbles. What is the probability of picking a red marble in the ANY of the first five consecutive tries, without replacement?</p>
<p>Writing:
The committee convenes (monthly) in the conference center where (they discuss) problems in the school (and) the ramifications those problems (have) on the students.</p>
<p>CR:
The children broke down in tears when their caretaker _______ scolded them with severe, acerbic insults.</p>
<p>Hmm I thought I saw that somewhere on this forum.</p>
<p>Anyway, for the math question, you first want to find the probability of not getting a red marble which turns out to be (7/10)(6/9)(5/8)(4/7)(3/6) = 1/12. The probability of getting a red marble is just 1 - 1/12 = 11/12.</p>
<p>The writing question has an improper plural pronoun, they, referring to the singular antecedent, “the committee.” The answer is B.</p>
<p>Caustic = harsh, biting, as of criticism
Temperately = moderately
Quiescently = in a calm way. I think of quiet.
Diffidently = in a shy way.
Ostensibly = pretentiously.</p>
<p>Acerbic is basically the definition of caustic. I think both sometimes denote sarcasm, but I’m not sure. In any case, the answer is A.</p>