<p>in how many different ways can five students of different heights be arranged in a line if the tallest student cannot be on either ends</p>
<p>Okay so I don't understand how the answer is 72.</p>
<p>Also I want to ask about probability problems. I don't understand how to solve it.. </p>
<p>Thank!</p>
<p>It is 4 * 3 * 2 * 1 * 3 = 72</p>
<p>You position the tallest person -> 3 options
You position the next person -> 4 options
You position the next person -> 3 options
You position the next person -> 2 options
etc.</p>
<p>As HeyBud answered, think about how many choices you have to place each person. PWNtheSAT had this: [PWN</a> the SAT: Counting: Oh, the possibilities](<a href=“http://blog.■■■■■■■■■■■■■/2011/09/counting-oh-possibilities.html]PWN”>http://blog.■■■■■■■■■■■■■/2011/09/counting-oh-possibilities.html)</p>