Last MINUTE SAT MATH PRoblem (Blue Book)

Test Preparation
1

<p>In rectangle ABCD, point E is the midpoint of BC. If the area of quadrilateral ABED is 2/3, what is the area of rectangle ABCD?</p>

<p>A. 1/2
B. 3/4
C. 8/9
D. 1
E. 8/3</p>

<p>The answer is C.</p>

<p>This problem seems easy, but for some reason, I can't seem to "see" the way to solve it.</p>

<p>Last minute help, please!</p>

2

<p>I think this problem has been solved earlier in this forum, but still...</p>

<p>Draw lines from E to A,D and to the mid-point of AD. You've now chopped up the rectangle ABCD into four triangles of equal size & area.
Area(ABED) = area( 3 triangles) = 2/3, so area( 1 triangle) = 2/9.</p>

<p>Area(ABCD) = area( 4 triangles) = 4(2/9) = 8/9.</p>

3

<p>suppose the side of the rectangle is x
the the area of ABED would be = Area of ABCD - Area of Triangle EDC
= X^2- 1/4<em>X^2
= 3/4</em>X^2
so 3/4*X^2=2/3
solve for X^2 and it should come out to be X^2=8/9
Area of ABCD, which is side times side, thus comes out to be 8/9</p>

4

<p>Thanks for all the help! I'm sorry if this has been answered before; I checked the Sticky thread at the top, but couldn't see it.</p>

5

<p>Do you have a page/problem number so that we can add this to the stickied thread?</p>

6

<p>pg 807, problem 16.</p>

7

<p>barrelbowl - you could save everybody's time if you used the right pages numbers.
This one is 747 / 16 / <a href="http://talk.collegeconfidential.com/showthread.php?t=93274%5B/url%5D"&gt;http://talk.collegeconfidential.com/showthread.php?t=93274&lt;/a>
and it is on the "Consolidated" thread (post #12).</p>

<p>807/ 16 / is on that thread as well (post #17).</p>

8

<p>Oh sorry, I'm a little disoriented right now.</p>