<p>1)A glass weighed 20.2376 g when empty and 20.3102 g when filed to an etched mark with water at 4degrees Celsius. The vessel was now found to weigh 20.3300 g. What is the density of the solution? (The density of water is 1g/cm^3).....</p>
<p>2) How much 58% sulfuric acid solution is needed to provide 150g of H2SO4(sulfuric acid)?</p>
<p>mwahahahaha......</p>
<p>1) 1 g/cm^3</p>
<p>2) 150g</p>
<p>...wrong...</p>
<p>1) Beware of vessels filled to unknown marks with unknown solutions. Is the glass filled with solution to the etched mark? Is the density of water 1 g/cm^3 at 4 degrees Celsius, or does it change with the temperature?</p>
<p>2) Do you have a means of separating the sulfuric acid from the solution? If not, no matter how much solution you have, you won't ever have 150 g of sulfuric acid short of purchasing some or obtaining some from other means. Will some of the sulfuric acid be removed from the solution in the separation process? If so, at what rate?</p>
<p>3) Does it make sense to provide a title that sometimes uses capital letters to start a word and sometimes uses lowercase? Is it dangerous to ask someone how smart they really are with the grammatical error of "your"?</p>
<p>Regarding number 2, it may also depend on whether it's m/v or m/m.</p>
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3) Does it make sense to provide a title that sometimes uses capital letters to start a word and sometimes uses lowercase? Is it dangerous to ask someone how smart they really are with the grammatical error of "your"?
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<p>a) yes, it makes perfect sense. Why? Because it doesn't have to be grammatically correct (believe it or not, this is not an english essay) :O</p>
<p>b) "your" is not a grammatical error. It is/was a technical (typing) error. </p>
<p>you obviously have no idea how to answer the question. it might be because the question is ambiguous, it might be because you don't know how to do basic chemistry. It might even be because you're too busy correcting things that don't need to be corrected. I guess I'll never know o_O.</p>
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believe it or not, this is not an english essay
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<p>Should this an I correct is be I essay this English using syntax argument hate so English?</p>
<p>[I hate this argument. This isn't an English essay, so should I be using correct English syntax?]</p>
<p>Even without an essay, people should take pride in the way that they write. Frequently, one is judged by it, just as one is often judged by the choice of words that they use in oral conversation. For instance, the implication from the question was the implication that the OP is smarter than the other people who might read the particular posting because the OP is capable of solving these problems. It is my experience that posts that come from such an attitude are often responded to with a bit of derision and insult. Perhaps this is a sad commentary on the nature of posting on internet forums. Perhaps this is a sad commentary on our willingness to be proud of our mistakes, rather than to take ownership of them and to strive to be the best individuals that we can be.</p>
<p>Alas, I digress from my point in responding further.</p>
<p>The real life constraints of chemistry questions show that the questions as asked had insufficient details. While my commentary on grammar, punctuation, and style may not have been required of the question, your failure to address the other legitimate issues might suggest that you're not exactly sure how to do so.</p>
<p>I am not a chemistry expert, but looking at the question, it seems to me that a basic understanding of mathematics and simple algebra is all that's required to solve the question. Under the assumption that this is the case, and assuming some of the constraints that were ignored by the original poster as being irrelevant to the question, I'll attempt an answer. It might be wrong. C'est la vie.</p>
<p>(1) The weight of the water when filled to the height of the etched mark is .0726 grams. The weight of the solution when filled to the height of the etched mark is .0924 grams. If the density of the water is 1 g/cm^3, then the proportion of .0726/1 = .0924/x applies, where x represents the density of the solution. Solving for x yields approximately 14/11 g/cm^3.</p>
<p>(2) If the solution is 58% sulfuric acid, assume that the sulfuric acid can be removed without decay. Then 58% of x should be equal to the 150g of sulfuric acid, and in solving for x, there should be approximately 258.621 grams of solution in order to remove 150g of sulfuric acid.</p>
<p>I hope you find my reply to your satisfaction.</p>
<p>1) wrong
2) wrong</p>
<p>@kyledavid...lol, you try so hard. It's too bad your post didn't weaken my point in the slightest bit....keep trying though.</p>
<p>I'm taking AP Chem and I can honestly say I have no idea even where to start on that problem. Man, I feel really behind in comparison.</p>
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@kyledavid...lol, you try so hard. It's too bad your post didn't weaken my point in the slightest bit....keep trying though.
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<p>Nice reply -- notice how you didn't actually address what I'd said.</p>
<ol>
<li><p>258.621 grams of 58% H2SO4</p></li>
<li><p>no idea and #2 is prolly wrong.</p></li>
</ol>
<p>correct for #2</p>
<p>Somebody gave that same response earlier and you said it was wrong...</p>
<p>
[quote]
1)A glass weighed 20.2376 g when empty and 20.3102 g when filed to an etched mark with water at 4degrees Celsius. The vessel was now found to weigh 20.3300 g. What is the density of the solution? (The density of water is 1g/cm^3).....
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this doesn't give enough information</p>
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The vessel was now found to weigh 20.3300 g.
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that's cool an all, but it would be nice to know what we are doing with this "solution." filling it back up to the etched mark? that's what I would assume but the question never says it...simply goes from filling 4 degree water up to a mark to saying some solution never even mentioned in the problem weighs a certain amount..</p>
<p>1) at 4 degrees celsius, water becomes slightly denser than at room temperature. Why? This is because at 4 degrees, water can get as close to forming ice as possible, but not form ice. Remember that the structure of ice is hexagonal, meaning that there's lots of space in between. Ice is less dense than water, which is why it floats in water. So at 4 degrees, I'm guessing water is about .98-.99 g/cm^3.</p>
<p>I'm not too sure about how to apply it to this problem, though. :P</p>
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Somebody gave that same response earlier and you said it was wrong...
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<p>I'm glad I'm not losing my mind. I was thinking the same thing. :)</p>