<p>Was the marble question a write-in or multiple choice?</p>
<p>I don't remember the exact wording of the stamp question, but I'm positive it was 85.</p>
<p>My friend claims the stamp question said that they plugged in 75 instead of 55 and 70 instead of 80....is that right?</p>
<p>The marble choice was a grid in, and 3. I put dont remember next to it in my previous post.
mbbuk55 almost. They put in 75 instead of 55 and 88 instead of 78 so you need to take out 30 from 10xAvg=85 as the new average.</p>
<p>no it was like, they plugged in 75 instead of 55 and like 87 instead of 77 (i'm not sure of those were the exact numbers) something like that you had to take their original average (88) multiply it by 10, since there were 10 people, that's 880. You take 880 - 30 (because they accidentally counted 30 more than there really were), that's 850. Take 850/10 = 85 <--the new average</p>
<p>Oh ok...that's the problem. He read it the way he saw it and he subtracted 20 and added 10 to get an average of 87. Tough luck there...cuz he knew what he was doing he just read it wrong.</p>
<p>do any of you guys remember if there was a question that goes something like ax^2+bx^2+cd+ad and they give u value of c-d or something similar liek that?</p>
<p>how about this one: the cost of n+5 apples? Experimental?
I got C(n+5)/N.</p>
<p>that's experimental . . .</p>
<p>Wow the posts are going so fast its practically a chat room. Someone else ask something, or check my grid in answers, if theyre the same or not.</p>
<p>The answer is 12pi, 24, and 85. These I am sure of. Stop asking, all three are the correct answer. As is the p=12 one.</p>
<p>was the question where the answer was T an experimental? b/c i don't remember that question</p>
<p>hyp, what was the p=12 one. I got that answer but dont remember the question.</p>
<p>Hey, I got a question that said:</p>
<p>You have two line segments, they are equal in length. Each end of the lines has a point on the circle. Now you have point M. Which of the following is true?</p>
<p>I. Point M is outside the circle
II. (like Point M is inside circle or something)
III. Point M is the center of the circle </p>
<p>I said only II and III</p>
<p>Anyone else have this one?</p>
<p>Yep. It wasn't experimental, either. The answer is E. I II and III. I works definitely.</p>
<p>Ok, how the hell do you have a point OUTSIDE the circle and also have the point be the CENTER of the circle, hmmm? **I know I and III are the correct choices.</p>
<p>Programmer I got all three are correct. Make Point X (-5,0) and Y (5,0). That would mean (0,0) is the center, and the upper boundary of the circle is (0,5) If M was (0, 1000) or anything else with an x coordinate of 0, the XM and YM would be equal.</p>
<p>Note: The points i gave were not in the problem, but just random ones that demonstrate the answer.</p>
<p>for that one it said on a circle where points A and E lie on the circle (not sure if those are the exact letters for the points) and then a point M is added and line MA and ME were equal which is true and the answer I am almost 100% sure is E 1,2,3</p>
<p>I was imagining that the two line segments were radii of the circle connecting at point M at the center of the circle. By definition and according to the problem, that's what it sounded like. However, I first started out drawing to line segments tangent to the circle, meeting outside the circle at Point M, but then realized it made more sense that they are radii of the circle. But listen,</p>
<p>It's impossible to have the same point on the inside of the circle and outside, and as the center at the same time. It just doesn't work that way.</p>
<p>Programmer, it asked which are possible locations of M. All 3 are possible, not all 3 are simoultaneously true. It never said M was inside the circle, just that points X and Y were equidistant from it. X and Y were points on the circle.</p>