<p>m = (555-x + y)/y</p>
<p>Was that answer choice "C"? I had run out of time and just guessed "C" on that phone call question.</p>
<p>are you guys sure the ying yang question was 12P ? i got 6P
it said the radius of a small circles was 3 which would make the radius of the big circle 6, and it asked for the circum of the shaded region, which i think was 1/2 of the whole circle, so 2PX6/2 =6P???</p>
<p>I got 6 pi, too, but I think I was finding the wrong thing for the question... maybe that's why it's 12 pi? Man... for the circle question, I thought it asked to find the last point to complete the circle's outer boundaries. Based on what I've read from fellow posters, the question asked for the center of the circle... d'oh!</p>
<p>Ying yang? That's what it was? O_o Funny, I didn't notice. I got 12p as well. The radius of the smaller circles is 3, which makes the diameters of the small circles 6 and the diameter of the large circle 12. The circumference is pi * diameter...</p>
<p>you only counted the half of the big circle...but u didnt count the parts of the little circle that were also part of the diameter...6pi was the upper half...and since each little circle had 3 as their radius...half of the circumference was 3pi...so 6pi+3pi+3pi=12pi</p>
<p>there was another question, and i can't remember the specifics (I really hope it's experimental):</p>
<p>which of these is never possible:
x^2 < x^3 < x
x < x^2 < x^3
x^3 < x^2 < x</p>
<p>and other variations...</p>
<p>DETSAzn, the answer was the one with x^2 as the lowest. That doesn't happen.</p>
<p>what is approx 4 wrong on the math = to? (2 of those, were omits)</p>
<p>what was the free response question that had 10 as an answer?</p>
<p>I still think it's 6pi...but I don't know for sure because I don't remember how the problem was worded...
that whole debate reminds me of that 15pi 8pi <em>or something like that</em> ordeal on one of the previous SATs where everyone on this board freaked out hahaha..wow
ALso...if you make a cube..out of paper...and draw right angles on it...I can find 24 that aren't repeated...I don't understand the logic of having it be anything else...
4 right angles per square..and stick them together and youll have 4*6...right?
or did I read this question wrong...</p>
<p>AGHhh...I jsut had to go to the bathroom through the whole test...damn my stupid venti coffee...it killed me!</p>
<p>oh crap...wait what was the square question asking?? ughhh now I'm all confused</p>
<p>ok, for the water pail question if i put .333 instead of 1/3, would that be OK because i know w/ .333 it doesn't work out exactly</p>
<p>i'm almost positive that .333 would work</p>
<p>.333 works, .333 works...but .33 or 0.33 doesnt</p>
<p>for the absolute value equation problem, is "0.5" ok or not? (was a student produced answer one, i believe)</p>
<p>yes thats perfectly fine. does anyone remember the free response question that had 10 as an answer?</p>
<p>Hmmm...I have some new thoughts for the cube one. The answer is 12 if we count the right angles that's formed by two discrete edges EXACTLY ONCE. The answer is 24 if we count at the vertices, which means we are counting each angle EXACTLY TWICE. My original argument was that, if we are able to count it twice, we should be able to count it infinity number of times, therefore 24 cannot be the right answer. But now that I think about it, I guess we could say that at each edge of the planes, the two planes are intersected perpendicularly by two different planes. To borrow some notions from Calculus, we could say that at each edge, the plane is actually separated into three sections, two at each extrema, and one in between. Since these are three discrete sections, we could say that two different right angles are formed at the extrema, which gives us the answer 24. Or we could even go as far as to say that the three sections are all different sections, and that we must count three angles at each edge, which gives us the answer 36.</p>
<p>The more I think about it, the more I am sure that this question is going to be thrown out.</p>
<p>can i get over a 700 with 4 or 5 wrong?</p>
<p>is it just me or does noone remember the car traveling in two directions along the same path at teh same speed questoin. I found the time for both directions using d=rt, got .75 hours, then i plugged that back in with the total distance, 20 miles, 20=r*.75 and got, 26.66. it was a plug in i believe towards the end of the section, maybe even the last one. anyone else get this?</p>
<p>also was the fence problem 101, add 1 because their are fences on either end... water tanke 1/3. but someone was saying the rate given was per 2 min but i dont remember that. then the one about parable, i found the vertex x value which was 3.5, then found distance between given x-intercept which was like 5 i believe, and added 3.5 another 5 which was 8.5, to get the other x value for the x-intercept...also the disance between pt (13,0) and circel with radious watever they give centered at origin, just do 13-r correct?</p>