<p>anyone else?</p>
<p>the one with x-y/x+y or sum s h i t = 2/3 , the answer was 3/5 when u multiply the top by 9 and the bottom by 10</p>
<p>yea, assuming that one was straight multiplication and i didn't screw up heh</p>
<p>oh snap i got 91</p>
<p>Do you remember what the question was about?</p>
<p>recalculate the average question</p>
<p>i got 91 on the average too
i actually drew out all the terms and made the mistake that the problem supposedly made, then recorrected it as asked to check</p>
<p>I took 88 x 10 terms, subtracted out the numbers they got wrong and reentered the correct numbers, maybe i made a mistake in reading the problems and subracted out the correct numbers and re-entered the wrong ones.</p>
<p>i need more confirmation on the recalculate the average question!!!</p>
<p>I got E, the lower one which was not 91. It was 85 or something.</p>
<p>Recalculate the average was 85. The incorrect sum was 880, which is 30 more than what should be (one number was entered 20 higher, the other entered 10 higher).</p>
<p>Also, back to the square vertices question. The answer is 24 for the following lines of reasoning:</p>
<p>A: Each side has 4 right angles and there are 6 sides. No right angle lies on two sides, so each of these are distinct. Thus there are 4*6 = 24.</p>
<p>B: Each edge takes part in 4 right angles (2 at each vertex). There are 12 edges on a cube, but the right angles are NOT distinct. Rather, each is shared by another edge. Therefore, the answer is 4*12/2 = 24.</p>
<p>C: Each vertex has 3 right angles. Each of these is distinct, since no right angle belongs to more than one vertex. There are 8 vertices to a cube. 3*8 = 24</p>
<p>For those of you that got 91 as the new average, you must have added 30 to 880 instead of subtracted it.</p>
<p>(I also got E) 85)</p>
<p>Ugh, you know the question where it was like two digit numbers with units number as a 5 that are prime? I got that wrong, cuz i counted 5</p>
<p>Yeah - me, too. It's not that I thought 5 was a two-digit number (it's obviously not), but I forgot that the question said "two-digit number," so went back and added 5 to Set B after putting 15, 25, 35,... which was obviously really dumb.</p>
<p>it was def. 85 guys, you had to subtract 30 from 880 to get 850, then divide by 10 = 85.</p>
<p>what about that one question where it gives you 5 graphs as answer choices.
something about intervals, i think it was like 10% discount lstarting from $500 like every month or something...... and then the discounts stop at like half the original price .
anyone remember that one??? definitely not experimental</p>
<p>okay lets reason this out:
the question said that the average of 10 numbers was 88 and that the number they used for this average was 30 more than the actual right?
so that means that x/10 = 88. x=880. but this total was 30 more than the actual so u need to subtract 30 from it and u get 850. C.RAP AHHHHHHHHHHHHHHHHHHHA DAMNNNNNNNNNNNNNNNNNNNNNN i did so bad on this test</p>
<p>yes i remember the graph question, what you were suppose to do is look at the graph that had a plateau from 1-2 at 450, then a pleatau at 400~, and then 360~, etc etc...until it reached about 250 where it was a final plateau all the way...</p>
<p>ok that is what i put... but there could have been some trick to it for i thought it was too easy</p>
<p>got 85 for the average as well.. i soo bombed the math and i think i owned the CR and Writing..lol it must be nearing the end of the world..</p>
<p>yo guys i have one question, you know that last math section, the 20-minute one with something like x^2 > x > x^3 and those questions, is it possible that that section could be the experimental section even though it was only 20-min, because i know i had an extra math section. btw the reason i'm asking is because out of the 5 i omitted in total for math 3/4 of them were in this section..(i omit because i'm paranoid, i'm fairly sure 99% of the questions i did in fact answer are correct)</p>