March 2012 SAT I Math Thread

<p>a 48/54 is like a 670/680</p>

<p>not it was 234… 2+3+4=3x3</p>

<p>Can someone please explain the one at the end of the section with the circle with a tangent line, right angle with the radius of 1, and you had to find the area of the quadrilateral?</p>

<p>yikes. I THINK I only got 1 wrong (this was in the fill in section, not MC) and 1 omitted, maybe 2 wrong, but that would be frustrating if I got under a 700 math. I hate how steep of a curve the math section has.</p>

<p>@Diatomiclove. You divided it into two sections and because they are both right triangles the height is 1 and we know that both lengths are 4. the area of a triangle is 1/2hb but you had two of them, so it is 2 times 2. The area of the section was 4. Anyone else agree?</p>

<p>caruso, yeah you divide it into two triangles; guys, does anybody remember any of the problems on the 16 question math section… I really rushed that section and want to compare answers? Anybody :)?</p>

<p>@jimmypod oh yea! …so it was 6400 right? Because (20 x 20) x 9 = 3600…which was the area of the 9 white squares. I have a couple of questions: for the xy coordinate plane with (something, 4) … I forget what the “something” was. But there was the (0,0) as the center, and a (something, 4)…and it asked was the (b, 0) would be. So basically it was asking for the base. Does anyone know how they did that? And, another question about scalene triangle with degrees 45, 75, and 60 (I think)…and they gave ONE side to be “something” (I forget) square root of 3…and you had to find the other side. It was the last question on 25 min. section I believe. How did one approach that one? Thanks in advance =)</p>

<p>@Caruso707 yup i got 4, for the same reason</p>

<p>annaanna, you use the law of sines; does anybody remember problems from the 16 question section?</p>

<p>@howmanyofme, you mentioned to use the law of sines…for which one? or Both? And, how would that apply to that certain problem? Thanks.</p>

<p>@howmanyofme did you get answer choice E for that? it was 6+6(sq.rt.)3, i think.</p>

<p>it was for the triangle one on the 20 question section.
you had to do
a b
----= ----------- in this case you would have solved for side B.
sin a sin b</p>

<p>did you get the 6 + 6(sq.rt. of 3) one?</p>

<p>yes I did, do you remember any questions from the last section ?</p>

<p>Any hope that -1 will be 790?</p>

<p>I have heard 780, but it is a possibility. In the end there really isn’t much difference between a 780 and 790. They are both almost always 1 wrong from what I have seen.</p>

<p>I agree with how many though, does anyone remember the harder ones from the 20 min section? I am drawing a blank.</p>

<p>if you tell me some of the ones from the 16 question one … ill be more than happy to help you on the 20 question one . -.-<em>sigh</em></p>

<p>there was one where it was like, 8y>10 and 4y>something, idk, and it asked for the smallest possible integer value of x. i got 21, or 11, whichever was the largest choice available. verify?</p>

<p>I think it was 11 and I got that too. I think that was one of the easier ones though. </p>

<p>Was the question about the 9 minute phone call in the 16 Q section?</p>

<p>@spicyhot, I got 11 as well. The others (including 10) couldn’t be right.</p>