March 2012 SAT I Math Thread

<p>@annaanna926 for the 6+3 square root 2 question i used law of sines, which basically says sinx / x = siny / y. You have the side length across from the angle of 45 degrees (it was 4 sqrt 3 i think). The angle across the side you want is 75 degrees. So sin45/ 4sqrt3 = sin75 / y. And you just have to solve the equation.</p>

<p>There’s probably a different way to solve it too with special triangles, since the sat i isn’t supposed to include trig. but this was just faster to see for me</p>

<ol>
<li>I said 210-55=155 I think</li>
</ol>

<p>Sent from my SCH-I510 using CC</p>

<p>i agree w/ all of them. :o; btw. 6 was the difference in the g(x)=f(x)+4 graph.</p>

<p>I got the same answers for 31 and 32</p>

<p>shaded triangle? was that experimental?</p>

<p>again, what was the crayon one?</p>

<p>No. probability question </p>

<p>Sent from my SCH-I510 using CC</p>

<p>do you guys remember an answer that was b=2</p>

<p>Not crayon, sorry. It had a chart of all the colors that students liked and asked how many didn’t like yellow.
Sent from my SCH-I510 using CC</p>

<p>OHHHHHHHHHHHHHH yeah that was 155.</p>

<p>29 is correct. Are you sure it is shaded triangle? I thought it was just a triangle, which in that case would be 1/3</p>

<p>Does anyone know the exact range that was acceptable for the one where the area of the triangle had to be in between 5 and 9 and you were solving for a. I put a=3, Is that correct?</p>

<p>and for the 6 + 3rtwhatver, you are given enough angles to reason that:
triangle is pointy-end up, base on bottom.
Bottom left angle is 45. Bottom right angle is 60. Top angle is 75.
Draw a vertical line that intersects the top angle.
You now have a 45-45-90 triangle on the left, a 30-60-90 on the right.
Use basic trig to find the length of the smaller triangles’ bottoms and then add them together.
You know that the right side of the BIG triangle is 4 root 3. It is facing the 90 degree angle.
So, the side facing the 30 degree angle is 2 root 3. And this side is the bottom of the triangle. So it’s part of your answer.
YOU CAN STOP HERE! Only E gives you an answer with # + 2 root 3.</p>

<p>For the remaining side, 60 degree, you can multiply 2 root 3 by root 3 = 6
It’s also part of the 45-45-90 triangle. It faces the 45 degree angle.
The other side that faces the 45 degree angle is also 45. And it happens to be on the bottom of the triangle.
So add 6 to 2 root 3 and presto!</p>

<p>Hopefully this clears up this law of sine trig stuff.</p>

<p>Oh! That was pretty simple. I was freaking out for a moment there. @yetanotherperson, thank you…I understand now.</p>

<p>OHHHHH that shaded triangle thing. What grade did CB think we’re in? That was a waste of space…</p>

<p>thanks for the clarification for that question @Lanayru.</p>

<p>^^^ for the 6 to 2 root 3, one =)</p>

<h2>yeah the b=2 one was really simple just set x equal to 0.</h2>

<p>still -0 . hopefully get 800 :D</p>

<p>**** haha I misread and only saw the triangle portion. didn’t know it had to be shaded.
Does anyone know if that question was in the experimental section? </p>

<p>ALSO I think section 6 was the experimental section as I’ve been on the writing thread and people said they got sections 2 and 6 for grammar. I got section 2 for grammar and section 6 for me was math. And I know math had to be my experimental section since i had four of them.</p>

<p>^I didn’t know that experimentals all had the same number :stuck_out_tongue:
Couldn’t you just take a look around your room? If not everyone has their calculator out, it’s the experimental <em>le gasp</em></p>

<p>I got a CR with 23 questions that was the experimental (again). Didn’t know it at the time… I need to count better…</p>