<p>Assuming I misread the question for min/max and the answer is 6 (I had 8), that puts me at -1. Hopefully I didn’t make any other dumb mistakes that haven’t been posted yet.</p>
<p>I’m expecting
-1 Math (770-790?)
-1 or -2 CR (800?)
-1 or -2 W, probably 8-10 essay (hoping for 750+)</p>
<p>Does anyone remember the exact wording of the question that involved 7 numbers whose average is 0?</p>
<p>@voytek</p>
<p>yeah it was “the average of 7 numbers is 0 and the average of 6 of these numbers is 5. What is the 7th number.”</p>
<p>basically, 6 of the numbers sum up to 30 since x/5=6, solve for x and x = 30 (sum of 6)
so in order for the average to be zero, the seventh one had to be -30 or choice A.</p>
<p>I agree with that eagles. Does anyone remember what the one that gave said there was a set of positive odd integers containing n numbers and positive even integers containing n numbers. What is the difference if some sort of operation was done? I got 7 but I don’t know if that was right.</p>
<p>Anyone know the answer to the above?</p>
<p>Sounds like experimental</p>
<p>I really, really hope it was. I thought it was in my real one, but I am not sure about that.</p>
<p>nah i dont remember that one at all so definately experimental.</p>
<p>@bruceparkelee</p>
<p>the quad one was in the 20 question section while the triangle one was in the grid in</p>
<p>so I dont know what your talkin about?</p>
<p>@bruce</p>
<p>nah I wouldnt worry too much. I also remember getting two 4’s. But if you changed the between 2.5-4.5 to 3, nothing to wrry about.</p>
<p>nah my calc history was deleted</p>
<p>bruceparklee, they were on two completely different sections. One was on a fillin the other was on an MC</p>
<p>but im 99% sure your fine… ok screw it 100%. there no more worries</p>
<p>did we ever figure out the triangle one with the radius of 1 and the tangent point? and the area of quadrilateral OABC? I don’t think it could have been 4. because one of the sides was NOT the diameter. if it was the diameter then the figure would have had an area of 4. (since the diameter was 2 and the point of tangency was 4,0) it was a little less then 4 so i put 3 but i was unsure.</p>
<p>littlemeow , I like your logic, and I almost fell in the same trap. It looked like the area was less than 4 because the exact triangle wasn’t there… but after I looked at it for a while, I just figured that the quadrilateral could be split into triangles, each of which had a respective area of 2. 2 x 2 =4 . The area was 4 … I had 3 at first as well, but quickly changed my answer. If somebody could confirm 4 as the answer that would be great.</p>
<p>What was the answer to the question where x-y is given and then we’re asked what (x-y)^2 is?</p>
<p>And what was the answer to the question that asks what the remainder is?</p>
<p>ugh noooo 
haha i hated that question!</p>
<p>There was also a question where the volume of a cube is given and then the question asks for the area of the cube or something along those lines.</p>
<p>Do you guys remember the answer to that one?</p>
<p>^ the answer was 9.</p>
<p>bruce I cleared my history, what do you need help on >:(?</p>