<p>I think pentagon was experimental, but I got 10 for the record.</p>
<p>EDIT: @giants, f(x)=6, but I think the question asked for x and f(3)=6 which would make the answer be 3.</p>
<p>Was the experimental section the one that ended w/ RT = 1000? It was the 4 circles problem and you had to find the perimeter of /\ABC.</p>
<p>How to solve the parabolic one:
Given: (4,-1)
Formula: x2 + kx + 15
I just plugged it in:
-1 = 16 + 4k + 15
-1 = 4k + 31
-32 = 4k
k = -8</p>
<p>Plugging in (5,0):
0 = 25 - 40 + 15
0=0</p>
<p>Most recent consolidated list courtesy of jersey13</p>
<p>
</p>
<p>Does anyone remember the problem where “1 is the remainder of x + 3” (include answer choices if you remember please)</p>
<p>Thanks!</p>
<p>luca not that one with the graphs
it was the one that was like c is a constant and k= 3 and f(x) = 3 +x and f(3)=5 and g(x)= kx what is g(3)</p>
<p>@APisAwesome</p>
<p>A number divided by 7 has a remainder of 5. If the number is x +3, what is the remainder?</p>
<p>5 + 3 = 8
8 - 7 = 1 <— simple arithmetic</p>
<p>when a number n is divided by 7 there is a remainder of 5, when the same number n is divided by (x+3) what is the remainder. </p>
<p>Answers:
5,4,3,2,1</p>
<p>The answer is one, most of these were plug & chug…</p>
<p>giants - oh right. Yeah that one’s 6; I’m 99% positive it was confirmed earlier</p>
<p>What was the question for A: 1520?</p>
<p>For integers x and y</p>
<p>Which of the following MUST be positive?</p>
<p>I. x^2 - y^2
II. (y-x)^2 or maybe it was (x-y)^2
III. Something.</p>
<p>My answer was II, anyone confirm?</p>
<p>the one where its 43 degrees did the angles add up to 89 and not 90</p>
<p>“9 is difference of similar triangle perimeters”</p>
<p>anybody remember the problem? I remember the triangles were similar and had a proportion of 2/3…and had x and y…can anyone recall the lengths o the other sides?</p>
<p>I remember getting 1520 for a question. Was that a fill in?</p>
<p>What was the answer to the triangle one, when there were three midpoints and one triangle inside of another, and abde had area 1, what was the other triangle’s area?</p>
<p>
the smaller one was 4,6,8 the bigger one was 6,9,12. Add the two triangles up and subtract. 27-18 = 9.</p>
<p>@xImagine</p>
<p>The smaller triangle’s perimeter was 18.
The larger triangle’s perimeter was 27.</p>
<p>The smaller triangle had sides equalling 4,6,8.
The larger triangle had sides equalling 6,9,12.</p>
<p>I forgot which ones were given and which ones you had to figure out. :/</p>
<p>What did y = when 2sq(x) - x^(y-2/3)= sq(x)</p>
<p>@boston I got that for a fill in. The question was something like (3)(5)(7) = (1/2)(20+something)</p>
<p>@imagine/avidstudent You had to find the 8 and the 12 (larger triangle)</p>
<p>Live: y = 2</p>