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1

<p>what are the asymptotes of (x + 1)^2/9 − (y − 1)^2/16 = 1? </p>

<p>thanks!</p>

2

<p>The hyperbola has center (-1,1). The slopes of the asymptotes are +/-(4/3). The equations of the asymptotes are y-1=+/-(4/3)(x+1)</p>

3

<p>could you explain a little how you got there?</p>

4

<p>For a hyperbola in the form (x-h)^2/a^2 - (y-k)^2/b^2 = 1, the slope of the asymptote is ±b/a. This can be proven using calculus.</p>

<p>The center of the hyperbola is (h,k).</p>

5

<p>great, thanks!</p>