<p>The graph of x^2=(2y+3)^2 is</p>
<p>A)Ellipse
B)Parabola
C)Hyperbola
D)Circle
E)None of those</p>
<p>Book says the answer is C</p>
<p>HOWWWWWWWWWWWWWWWWWWWWWW???</p>
<p>it is because u subtract (2y+3)^2 from both sides and u’ll have a hyperbola :)</p>
<p>Explain in more detail…
Any other answers PLZZZZZZZZZZZZZZZZZZ!!!</p>
<p>the form of x^2 - y^2 or vice is always hyperbola.</p>
<p>Can you please write the STEPS ???</p>
<p>bump… char10</p>
<p>its the form. For example a circle is x^2 + y^2
Hyperbolas are just x^2 - y^2</p>
<p>x^2 = (2y+3)^2
x^2 = (2(y+3/2))^2
x^2 = 4(y+3/2)^2
(x^2)/4 - (y+3/2)^2 = 0</p>
<p>This is a truly abstract form and I don’t think this is the equation of a hyperbola. My bet is that the answer is E or the book simply misprinted the equation. 20 bucks that this problem is from the Barron’s book.</p>
<p>[Degenerate</a> conic - Wikipedia, the free encyclopedia](<a href=“http://en.wikipedia.org/wiki/Degenerate_conic]Degenerate”>Degenerate conic - Wikipedia)</p>
<p>(x^2)/4 - (y+3/2)^2 = 0
is the equation of a degenerate hyperbola (which, in essence, is just the asymptotes). It looks exactly like a pair of intersecting lines. </p>
<p>Therefore, C is technically correct.</p>