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</a> i know you have to complete the square but i tried to do it and cant get the answer the book shows</p>
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<p>x^2=4y^2+12y+9
4y^2+12y-x^2=-9
4(y^2+3y+9/4)-x^2=-9+9
4(y+3/2)^2-x^2=0</p>
<p>So it looks like you get 2 intersecting lines.</p>
<p>Ty i see that the two lines intersecting are characteristic of a hyperbola but can you explain now the books method
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<p>If a^2 = b^2 then either a = b or a = -b.</p>
<p>So take the sqr root of both sides and get x = 2y+3 or x=-(2y+3), both of which are linear…</p>
<p>Whoever wrote that book made a mistake. It’s two lines, which you can see by taking the square root. </p>
<p>You can’t complete the square because they already are complete; if you tried expanding and completing the square you would get the exact same thing back.</p>
<p>Thanks everyone i get it now and yeah its barrons go figure, they barely explain and when they do its sometimes wrong…</p>
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