<p>Question: </p>
<p>Which of the following expressions, if any, are equal for all real numbers x?</p>
<p>I. √(-x)^2 (the square is under the square root)</p>
<p>II. |-x|</p>
<p>III. -|x|</p>
<p>A. I and II only
B. I and III only
C. II and III only
D. I, II, and III
E. None of the expressions are equivalent</p>
<p>Book answer: A</p>
<p>In the red book, there is a question that claims √(-x)^2 (the square is under the square root) and |-x| are equal. This does not make sense to me. It is clear that |-x| has to be positive, because absolute value is the offset from zero, and therefore must be positive. But I do not understand how the first expression has to be positive. </p>
<p>Lets say that x = 3. There are 2 ways that I know to evaluate this. </p>
<li><p>if x = 3, then -x = -3, and -3^2 is 9. the √9 = 3 and -3. </p></li>
<li><p>if x = 3, then -x = -3. because ^2 = ^(2/1) and √ = ^(1/2), then -3^((2/1)(1/2))
= -3^(2/2) = -3^(1) = -3. </p></li>
</ol>
<p>Lets say that x = -3 (remember that when x = -3, -x = 3).</p>
<li><p>Using the same method shown when x = 3 (now being used for x = -3), 3^2 = 9,
√9 = 3 and -3.</p></li>
<li><p>Using the same method shown when x = 3 (now being used for x = -3), 3^1 = 3.</p></li>
</ol>
<p>This last solution is the only one that works, but 3 is a real number and |3| = 3. If II has to be positive for a number x (a real number), and I = II, then I must equal II (for the same number x). Yet when 3 = x, I (think I) proved that II (|-3|) = 3, and I = 3 and -3 (using method 1) or -3 (using method 2). REGARDLESS of which method is more correct, there is still a -3 as an option for the answer of I, and the question asks for the 2 expressions that are equal for all real numbers. </p>
<p>Can someone please prove me wrong? Is my logic just flawed? </p>
<p>Thank you for reading!</p>