<p>In the figure above, ABCD is a rectangle with BC=4 and AB=6. Points P,Q, and R are different points on a line(not shown) that is parallel to AD. Points P and Q are symmetric about line AB and points Q and R are symmetric about line CD. What is the length of PR?</p>
<p>If you have the bluebook, you can flip to the #12 section 9, Practice test #2 or just page 490.</p>
<p>Actually, no matter what value you choose the result is always 8.
For example: PQ=4, so then QR=4. 4+4 still equals 8.
As long as PQ/2+QR/2=8 it will work. That is a given must.</p>
<p>sorry, I don't get this. I understand that symmetric about means it's bisecting the line. so wouldn't that be bisecting line ab which means it would be 6/2 = 3? so 3+3 =6?</p>
<p>Well, symmetric about the line means that it's equidistant from it, so...</p>
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P Q</p>
<p>where AB is the line most to the left (I haven't seen the diagram so I don't know how it actually is.)</p>
<p>Here, imagine that u extend AB so you have</p>
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P Q</p>
<p>the distance from Q to the extension of AB = distance from P to extension of AB (and since a line is infinite, the extension of AB is the line AB).</p>
<p>Now imagine extending CD too.</p>
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P Q R</p>
<p>Q to the extension of CD = R to the extension of CD, thus Q and R are equidistant from CD.</p>
<p>Now to get PQR, notice how (Q to AB) + (Q to CD) = 4 (length of BC, given).
Similarly, if (P to AB) = (Q to AB) and (R to CD) = (Q to CD), replace it in the equation above to get (P to AB) + (R to CD) = 4 too.</p>
<p>SO in total, (P to AB) + (Q to AB) + (Q to CD) + (R to CD) = P to R = 4 + 4 = 8.</p>