<p>The problem where there was a triangle with sides 3 and 4 on the grid ins, and they said that the angle was greater than 90, so what could the other side be? </p>
<p>The answer was anything greater than 5 and less than 7, right?</p>
<p>How many balloons did she want again, i'm writing it out because i got it and i forgot how many she wanted to make out of the 1-2g, 2-3r, 2-3b, 2-3yellow</p>
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The problem where there was a triangle with sides 3 and 4 on the grid ins, and they said that the angle was greater than 90, so what could the other side be?
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The balloon one was the only one I omitted. I didn't want to waste time counting. I know there must be a faster way to do it; anyone know what it is?
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Yeah.. It was like 2-3 red balloons, 2-3 blue, 2-3 yellow, 1-2 green</p>
<p>You do this:
2R (you can add 2 to this) | ---- 3R | ---- 3R | ---- | | ---- 3R
2B (you can add 2 to this) | ---- 3B | ---- 2B | ---- | | ---- 3B
2Y (you can add 2 to this) | ---- 3Y | ---- 3Y | ------ 3Y | ------- 2Y
1G (you can add 1 to this) | ---- | ----- 2G | | ---- | ----- 2G</p>
<p>Yeah, I know...but it's combination and you can arrange them in any order you want...notice I always have a 2 in the combos...or am I missing something?</p>
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And the one with the bounded parabola:
II was F(X) < Y, when the graph is initially: F(X) = Y, and every answer but "None" had II in it. So it was None
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<p>this doesn't make sense, but eh i'm confident, not arrogant.</p>
<p>oh and did anyone remember something like (x+3)(x+b)=x^2+cx+12 ????
they asked for C right, so it was 3b=12 so b = 4. plugging that in yeild c = 7 right?</p>