<p>Yes..I got 5/44...and two 48 for the grid-ins :) !!!</p>
<p>^ Thats what I got. 9the 2 circles on)</p>
<p>YAYY i got 4pi too!</p>
<p>for the circles, I put 4pi + 2...but I kind of guessed.</p>
<p>the parabola question was definitely II and III. Since the parabola was y = x^2 and it was bounded by y=4 at the top, the x values ranged from 2 to -2 thereby making the absolute value of x < 2. The other one said y > x^2, which is also true since the point (1,3) (just an example) was in the shaded region.</p>
<p>I got II and III for the parabola.</p>
<p>I also had 4pi :).</p>
<p>did anyone have a question where you're given 2 equations and you have to solve for c (for which there cannot be a pair of numbers x, y that can satisfy the 2 equations)?</p>
<p>i had 4pi as difference, and i also had II and III.</p>
<p>@berkshire: I got that one... the answer's -2/3 or something.</p>
<ol>
<li><p>abs value of X is less than OR equal to two as I just said</p></li>
<li><p>y is not greater than X for corresponding values of X and Y. Just because you can find 1 example does not make it definite, as there are examples where Y is not greater than x squared.</p></li>
</ol>
<p>@ berkshire: it was -2/3. 100% sure :)</p>
<p>for the parabola one, i graphed it, and looked at the table. For all values x, y was x^2...so y isn't > than x^2.</p>
<p>but idk.</p>
<p>
[quote]
YAYY i got 4pi too!
[/quote]
</p>
<p>Lmao, funny story behind that problem. That section was hard, and I had like 5 minutes left for questions 17, 19, and 20 (something like that. Pretend 17 was the 4pi problem). I was freaking out, needless to say. I got 19 in two minutes, worked on 20 for one minute, changed back to 17, back to 20, solved 20, then back to 17 with 40 seconds left. I kept thinking "sht sht sht, I hate this." There was like 20 seconds left, so I was like w\e, time to guess. The only number there was 2, so I figured "well, the bigger one looks twice as big as the smaller one, so 2*2 is 4, then circles like pi, so 4pi." Later on, convinced I had gotten it wrong I finished a section early and was thinking about the problem, realized how to solve it, did it in my head, and it was actually right. :)</p>
<p>which two questions were on the grid ins with answers as 48?</p>
<p>I had 4pi as well</p>
<p>we're all kinda split on the "none" Q </p>
<p>but i asked my older brother and he thinks its "None" for sure too
(then again older brothers can be wrong...)</p>
<p>The bounded region is above y=x^2 so any point (x,y) in that region has y > x^2</p>
<p>Am I missing something?</p>
<p>I.) xy > 0
II.) y^2 > x
III.) |x| < 2</p>
<p>ALRIGHT GUYS</p>
<p>do u remember the question where u had to find out b from y=mx+b</p>
<p>i got 2.666666 and I know I got it right</p>
<p>and for number 15 on the last math section it was y=2x</p>