<p>The bar graph above shows the number of students who were absent from Jackson High School each day last week. Of those students, 8 were absent exactly 2 days each, 1 was absent 3 days, and no students were absent more than 3 days. If 5 percent of the students in the school were absent at least 1 day last week, how many students are enrolled in Jackson High School?</p>
<p>The graph shows this data:</p>
<p>25 students absent on Monday, 20 on Tuesday, 10 on Wednesday, 15 on Thursday, and 20 on Friday</p>
<p>The answer 1600, but I don't understand or know how to get it.</p>
<p>First off, we start by adding up the total number of days of absenteeism:
20 + 20 + 10 + 15+ 20 = 90</p>
<p>Next we subtract the total number of days of absenteeism contributed by those who were late for 2 days or 3 days.</p>
<p>90 - 8 x 2 (8 people were late on 2 days) - 1 x 3 (1 person was late on 3 days) = 71</p>
<p>This number, 71, is the number of days of absenteeism contributed by those absent for a single day. Thus to find the number of students who were absent for a single day, we divide 71 by 1 which is 71. </p>
<p>Now lets look back at the question. It says 5 percent of the students in the school were absent at least 1 day. (This means 5% of students were absent for 1 day, 2 days, 3 days or more than 3 days (though no one was absent for more than 3 days)). Thus, we now have to count the total number of people who were absent for 1 day, 2 days or 3 days.</p>
<p>This is just: 71+8+1 = 80</p>
<p>Now this is only 5% of the number of students enrolled in the high school and since we must find the total number of students enrolled (100%), we take </p>