<p>2nd question
We know that the sum of sq root of x and the sq root of y is 10.
So list out the numbers the numbers that will add up to 10.
Lets just list all the single digits
1,2,3,4,5,6,7,8,9</p>
<p>The question states that x and y are odd, thus their roots must also be odd.
the odds are 1,3,5,7,9
Which one of these makes 10?
Lets choose 9 and 1.
so 9^2=81=x
1^2=1=y
1+81=82. </p>
<p>Sorry i don’t know how to solve that one algebraically so i just reasoned it out.</p>
<p>3rd question.</p>
<p>we are given that the circles are tangent, so rsp is 90 degrees.
The radius of the small one is 1, and the radius of the alrher one is 6.
We can just get segment PQ by adding the 2 radius because they create the triangles hypotenuse.</p>
<p>The radius of the bigger circle, pr, is 6, and is also the leg of the triangle.</p>
<p>Use pythagorean theorem</p>
<p>7^2-6^2 = 13</p>
<p>We want RS, which is on RQ.</p>
<p>This part is easy, we already know QS, qhich is the radius. so to find rs</p>
<p>the length of RQ = sq root of 13 - 1. </p>
<p>B.</p>