<p>The</a> Official SAT Question of the Day</p>
<p>I don't understand how to create an absolute value graph</p>
<p>An absolute value graph in this instance means that all the x values stay the same but all the y values become positive. You’re basically “flipping” all parts of the graph below the x-axis to above the x-axis.</p>
<p>Normally, x^2 - 1 would pass through (0, -1) but the absolute values makes it such that it passes through (0, 1).</p>
<p>You know it cannot be A or B just from looking at the graph. It’s a parabola that’s sort of reflected back upwards, so absolute value has to be involved. Then you plug in points. It appears that (0,1), (1,0), and (-1,0) are all points on the graph. C, D, and E all contain (0,1), but C does not contain (1,0), and both C and E do not contain (-1,0). So process of elimination leaves us with D.</p>
<p>Like Secret Asian Man said, it’s obviously not A or B. That leaves us with C, D or E. Instead of stressing my brain about it, I just plugged the answer choices C, D and E into my Nspire and saw the graph.</p>
<p>@Secret Asian man: How do you know there’s 1 and 0? I cannot see the points on the graph</p>
<p>help me please</p>
<p>2 ways to solve: </p>
<ol>
<li>Grouping standard</li>
<li>function transformations. A and B would give a graph that opens down. C would shift left and E would shift right. Only D is possible, shifting down and then doing the absolute value. </li>
</ol>
<p>Really, this problem isn’t that hard. Go look up function transformations in Gruber’s.</p>