<p>Could someone explain how to solve this problem?</p>
<p>The least integer of a set of consecutive integers is -25. If the sum of these integers in 26, how many integers are in the set?</p>
<p>Thanks!</p>
<p>since you are dealing with consecutive integers the sequence is -25,-24,-23,…26 u can model this by using the equation -25+x=26. solve for x and u get 51. however this equation doesn’t account for the zero inbetween the -25,-24,…0,26. therefore u have to add one. 51+1=52 so, there are 52 integers in the set.</p>
<p>Well, since the sum equals 26 and the last number is negative, you are going to have to go at least to 25 (opposite of -25). Once you do that, your value has to be 0. The next number is 26, and 26 + 0 = 26. There you go. Now just count the integers however you feel comfortable.</p>