<p>If n and p are positive integers and 3^n/p = root 27, then the product of n and p is</p>
<p>(A) -1
(B) 0
(C) 3
(D) 6
(E) 9</p>
<p>I tried, but to no avail. Can't figure out how to go about this problem.</p>
<p>For problems such as the above, there is value added to memorizing the perfect squares and cubes through 10.</p>
<p>27 is 3 cubed or 3^3</p>
<p>3 ^ (n/p) = sqrt (27) (Given)</p>
<p>3 ^ (n/p) = (27) ^ (1/2) (sqrt of a number is the number to the 1/2 power)</p>
<p>3 ^ (n/p) = (3^3) ^ (1/2) (Substitution of 27 = 3 ^ 3)</p>
<p>3 ^ (n/p) = 3 ^ (3/2) (Multiply the exponents when raising to power)</p>
<p>The exponents need to be equal so n/p = 3/2.
Let n = 3 and p = 2. Then np = 6.</p>
<p>^ Yes. But n=6, p= 4 also works. So the problem needs a minor edit. Could be fixed by asking “One possible product…” or even “The smallest possible product…”.</p>
<p>Where is this from?</p>
<p>That is equal to the same fraction, pckeller. In this case, the answer would be 6 because that is the only acceptable answer out of the five options.</p>
<p>This is a poorly worded question, as it should be the product “could be” not “is” 6</p>
<p>3^(2n/p) = 27</p>
<p>n could be 3, p could be 2… n could be 12, p could be 8… and so on</p>
<p>Is the concept of multiple choice really that hard to understand? The answer is the best choice among the 5 given. </p>
<p>Do A B C or E work? Nope! </p>
<p>Overthinking is your nemesis.</p>
<p>^Thank you xiggi.</p>
<p>yes i have question on the princenton review book 2011 editiion
there is a question im confuse it here is the question on the number line shown above all the tick marks are equally spaced what is the value of m this in test 3 on section 8 page 245 question 13</p>