<p>If k is a positive integer, which of the following must represent an even integer that is twice the value of an odd integer?</p>
<p>(A) 2k
(B) 2k+3
(C) 2k+4
(D) 4k+1
(E) 4k+2</p>
<p>???
I thought that this question was really weird. The answer isn't (A) 2k.</p>
<p>thanks for your help!</p>
<p>That's a really really weird question... If you say it isn't (A), then I really have no idea. What's the real answer, and where'd you get the question from?</p>
<p>are you sure you typed it right?</p>
<p>E</p>
<p>i plugged in using k = 2.</p>
<p>4k + 2
8 + 2 + 10</p>
<p>10/2 = 5 </p>
<p>5 is an odd integer</p>
<p>ps: notice that C also works IF K= 3. however, it does not work everytime, answer E does.</p>
<p>The answer is E the question asked
If k is a positive integer, which of the following must represent an even integer that is twice the value of an odd integer? </p>
<p>so its 4k+2 </p>
<p>If you plugged in 1 you would get an even number 6? which is twice the value of the odd integer 3
If you plugged in 2 the answer would be 14 which is twice the value of the odd integer 7 its so damn easy!!!!!!!!!!!!!!!</p>
<p>im actually quite surprised that this one gave some problems...but then again, if i showed you some of the ones i've had problems with...be a different story...but yea man...it's pretty straight forward.</p>
<p>take a positive integar...try to REFRAIN from picking 1-5...those will sometimes work with all of the choices. Go into deeper, but still easier numbers...like 10. </p>
<p>A) 2 x 10 = 20... 20/2 = 10....even cross it out
B) 2(10) +3 = 23....cross it out
C) 2(10) + 4 = 24.... 24/2 = 12... cross it out
D) 4(10) +1 = 41 .... cross it out
E) 4(10) + 2 = 42. 42/2 = 21.....wabam</p>
<p>Another way is if you know that the standard way to denote an odd integer is 2k+1</p>
<p>2(2k+1) = 4k+2, E.</p>
<p>Um, so it's just... plug in, plug in? And as jenkster said... know how to denote an odd integer? Thanks!
haha... I don't know... I thought it was 2k right when I saw it but i found that it was wrong. Sorry, math isn't my best subject in the first place and my dad got ****ed when i asked him. lmao.</p>
<p>Even numbers are divisible by 2.
So, even numbers can be written as 2k, where k is an integer.
If 2k is even, then 2k+1 has to be odd.</p>
<p>It makes a lot of sense once you learn it.</p>
<p>E. I plugged in 6 initially, then I got 2 options C and E. As a result I tried a different number, 4, and E was the only correct option.</p>
<p>thanks for your help =)</p>
<p>It is E. For these kind of questions, I just plug in a value and see which option works. Simple, stress-free method :)</p>
<p>ANSWER = twice the value of an odd integer
ANSWER/2 = the value of an odd integer.</p>
<p>Answer (A) 2k ------> ANSWER/2 = k ------> odd only if k is odd
Answer (B) 2k+3
Answer (C) 2k+4 ------> ANSWER/2 = k + 2 ------> odd only if k is odd
Answer (D) 4k+1
Answer (E) 4k+2 ------> ANSWER/2 = 2k + 1 ------> odd for any k.</p>