<p>Please help me with these math questions with explanation </p>
<p>Test 3
section 2
number 18:
any 2 points determine a line. If there are 6 points in a plane, no 3 of which lie on the same line how many lines are determined by pairs of 6 points. </p>
<p>a) 15
b) 18
c) 20
d) 30
e) 36</p>
<p>secion 5
number 6</p>
<p>If x doesn’t equal 0 and x is inversely proportional to y, which of the following is directly proportional to 1/x^2?</p>
<p>a) -1/y^2
b) 1/y^2
c) 1/y
d) y
e) y2</p>
<p>section 5
number 8 </p>
<p>(x-8)(x-k) = x^2 - 5kx + m
In the equation above, k and m are constants. If the equation is true for all values of x, what is the value of m?</p>
<p>a) 8
b) 16
c) 24
d) 32
e) 40</p>
<p>section 8
number 13</p>
<p>IN a certain game, each token has one of three possible values: 1 points, 5 points, or 10 points. How many different combinations of these token values are worth a total of 17 points? </p>
<p>a) two
b) three
c) four
d) five
e) six</p>
<p>First question:</p>
<p>(A) Each point can have a line to every other point. Meaning line One will have five lines it can make with points 2 through 6. Line Two can make four other lines with points 3 through 6 but not a line with point 1 since a line has already been made between points one and two. Follow this pattern for each point and there will be 15 possible lines for the 6 points (5+4+3+2+1).</p>
<p>Second question: </p>
<p>(E)</p>
<p>1/x= y</p>
<p>1/x^2= y^2 –> Answer.</p>
<p>Third question:</p>
<p>(B)</p>
<p>(x-8)(x-k) = x^2 - 5kx + m
x^2 - kx - 8x + 8k = x^2 - 5kx + m
-8x + 8k = -4kx +m</p>
<p>Now, compare (-8x) with (-4kx),
-8x = -4kx
-8 = 4k
k = 2</p>
<pre><code> (8k) with (m)
8k = m (k=2)
m=16
</code></pre>
<p>Fourth question:</p>
<p>(E)</p>
<p>Basically, look for every combination of tokens that can make seventeen:</p>
<p>1 Token 5 Token 10 Token</p>
<p>2 1 1
7 0 1
2 3 0
7 2 0
12 1 0
17 0 0</p>
<p>^ Adds up to Six combinations.</p>
<p>thank you
for the 3rd question, why do you compare the terms separately? how are they equal?</p>
<p>You compare x values with other x values and non-x values with other non-x values since the two equations are equal.</p>