<p>3(3^x+1) = 9^x+2?
Can I do this: 3(9^x+1) = 27^x+2?
Thanks.</p>
<p>I may not be understanding the question properly but that makes no sense.</p>
<p>umm, i don’t think it makes sense either. when you have an equation like that, the easiest thing to do would be to go to the graphing part of your calculator, on Y1 graph
3(3^x+1), on Y2 graph 9^x+2, and then find the intersection point. much quicker than solving by hand.</p>
<p>I’m assuming you have the question written incorrectly. You probably mean this:</p>
<p>3(3^(x+1))=9^(x+2)</p>
<p>If this is the case, then here is how you would solve it algebraically:</p>
<p>3^(x+2)=(3^2)^(x+2)
3^(x+2)=3^(2x+4)
x+2=2x+4
x=-2</p>
<p>Sorry, I mixed the two questions.</p>
<p>1) Can I do this: 3(3^x+1) = 9^x+2?(Add the one from the initial 3 to x+2 from the other 3.)</p>
<p>2) Can I do this: 3(9^x+1) = 27^x+2?</p>
<p>No. You are not distributing correctly.</p>
<p>3(9^x+1) = 3*9^x + 3 = 3(3^2)^x + 3 = 3(3^(2x)) + 3 = 3^(2x+1) + 3</p>