<p>For the SAT i've been preparing by doing an online course and i have come across a problem i need help with and was wondering if you guys could help me out. The problem is this:
A vendor sells "h" hot dogs and "s" sodas. If a hot dog costs twice as much as a soda, and if the vendor takes in a total of "d" dollars, how many cents does a soda cost?</p>
<p>2s = h</p>
<p>2s + s = d dollars</p>
<p>thus a soda is 1/3 of the d dollars
so d dollars * 1/3 then * 100 for the cents?</p>
<p>so 100d/3?</p>
<p>Whe i look at the answer which is 100d/s+2h it gives me this explanation (A) Set up an equation. 100d=h(2c)+sc, where c=cost in cents of the soda. Solve for c.
However i dont know how they got 100d/s+2h. If you could explain it to me it would help me alot.</p>
<p>do you mean 100d/(s+2h)?</p>
<p>yeah I combined the 2 variables which should not be combined</p>
<p>Yes, i do mean 100d/(s+2h). Thank You for your help.</p>
<p>i hate these kinds of problems, is there a way to sub in values for it? or any general strategies for them?</p>
<p>was this a multiple choice question that u didn't list answers for?</p>
<p>Well, the question was this with the following answer choices and judging by the answer choices i doubt you can sub in values for it. I dont like these questions that much either.</p>
<ol>
<li>A vendor sells "h" hot dogs and "s" sodas. If a hot dog costs twice as much as a soda, and if the vendor takes in a total of "d" dollars, how many cents does a soda cost?
a) 100d/(s+2h)
b) (s+2h)/100d
c) (d(s+2h))/100d
d) 100d/(s+2d)
e) d/ ((100)(s+2h))</li>
</ol>
<p>Ok I have another SAT math question that i need help with.</p>
<p>On a street with 24 houses, 9 houses have fewer than 6 rooms, 8 houses have more than 7 rooms, and 4 house have more than 8 room. What is the total number of houses on the street that are either 6-, 7- or 8-room houses? </p>
<p>a)8
b)9
c)11
d)13
e)14</p>
<p>actually you can sub in, seting your own values and plugging them into the answers</p>
<p>is the answer c?</p>
<p>It's C, right?</p>
<p>I would list the inequalities in order so you can find the numbers you need.</p>
<p>8 houses have > 7 rooms and 4 > 8 rooms, then 4 have exactly 8 rooms</p>
<p>9 houses < 6 rooms, 8 > 7 rooms </p>
<p>subtract 4 w exactly 8 rooms</p>
<p>20 - 9 houses which have 5 or less rooms = 11
- 4 houses which have => 9 rooms
this leaves 7 houses 6-7 rooms</p>
<p>so 7+4 = 11</p>
<p>Another way to visualize this problem is to do a number line, and graph the inequalities they give you so you can find the unknown parts you want (6, 7, 8 room houses) and add them. That's a good way concise way to do it if this kind of protracted working-through on paper confuses you.</p>
<p>Feel free to keep posting questions.</p>
<p>9 houses out of 24 have 5 or less rooms ->
24 - 9 = 15 houses have 6, 7, 8, or more rooms.</p>
<p>4 out these 15 houses have 9 or more rooms ->
15 - 4 = 11 have either 6, or 7, or 8 rooms.</p>
<p>9 : 11 : 4 - interesting distribution of wealth on a 24 house-worth street in the 'burbs.</p>
<p>Yes, the answer is C</p>