t and r are multiple of 3 where r<t and k is a multiple of 3 where r<k,t what is possible value of k
A t-r-3
B (t-r)/3
c (t-r)/3 -1
It is C.
Simple plug and chug mathematics would do it.
Eg: let r = 3 and t = 12. The number of values that k can take is 2 i.e. 6 and 9. Which can be obtained by the expression in C.
I thought they ask value not the number of value ;X @scimathguy
@xigjii please try to type the question exactly as written; currently the question asks for a possible value of k. Assuming you meant r<k<t and that interpretation, all three are possible answer choices.
However the number of possible values of k is simply the number of multiples of 3 strictly between r and t, which is the number of elements in {r+3, r+6, …, t-3}, which is (t-r)/3 - 1. You can also plug and chug as scimathguy did.
I was reading both of the posts from @MITer94 and @scimathguy and I will have to disagree with those answers. Well if you pick C just make plug in.
R=3 and T=12 K must be 6 or 9.
So let’s try for which of the answers satisfy the conditions.
A) 12-3-3=9, it works
B) 12-3/3=3, it doesn’t work
C) (12-3/3) -1, it doesn’t work
So you can see A is your answer unless the OP missed something.
@Jr12317 If you saw my above post, if the question asked for a possible value of k in terms of r and t, then any of the answer choices work. For example, let r = 3, t = 102, so that k can be anything in {6,9,…,99}:
A) 102-3-3 = 96
B) (102-3)/3 = 33
For C), let r = 3, t = 105:
C) (105-3)/3 - 1 = 33
This is why I suggested OP to try typing the problem exactly as written to avoid such ambiguity.
Yep sorry about that @MITer94