May 2008 MATH II

<p>haha i must've mis-remembered law of cos b/c i used it and kept getting a smaller number; but i chose the number that was closest, which was 78 degrees. yay!</p>

<p>but dang it; i was really thought i got that probability question right...</p>

<p>what was the standard deviation one? i know that if the graph is uniform, than it should have SD of 0, but there were 2 graphs that were uniform.</p>

<p>i remember one. what was the answer to that question were it asked you for the coordinates of the point that was reflected upon y=-x??</p>

<p>first like 15 were ridiculously easy</p>

<p>@ fivewinks:</p>

<p>the orignial was something like (3,2)
so the reflection was (-3,-2) i believe</p>

<p>third quadrant... :/</p>

<p>oh, for that one i put the answer that was in the 4th quadrant, since the y = -x line runs through there, and it said it was reflected. It was like (2,-3) i think.</p>

<p>Yes sorry thats what I meant about the X=3 one, typo, I bit scattered. </p>

<p>Standard deviation one was the one with all the scores the same because standard deviation is a measure of variability and that had no variability (AP Stats finally helped me with something).</p>

<p>for the y=-x, I think they gave you 2,3 and the answer was -2,-3?</p>

<p>azneyes, are you sure?..thats what i thought at first but the point (-2,-3) doesnt run on the y= -x line...</p>

<p>edit// i could very well be wrong.</p>

<p>I put (-3, -2) 'cause I graphed it and it looked right lol.</p>

<p>didnt they give 3,2?</p>

<p>ohhh I remember that one I think I put (-2, -3) cuz that is the one reflects to (2,3) isn't it?
my memory is vanishing now...</p>

<p>@ dean and mizami: well at least we got the concept right, just take the negative of each ;]</p>

<p>@ some dude:its not supposed to be on the line. its a reflection:</p>

<p>think about it this way, the distance from each of the points (original and refleciton) to the origin should be the same and on OPPOSITE sides of the line.
if you drew a line between these two points you would create a line perpendicular to y=-x</p>

<p>(dont know if my explanation is right...)</p>

<p>for the law of cos 5,6,7 side one did anyone get 102?? or 112? something along that line cause i did.</p>

<p>i put (-2,-3) at first but then i thought about the definition of reflection and doesn't the new pt have to be perpendicular to the line of reflection? so i changed my answer to something :(</p>

<p>i think, y=-x should be reflected over...the y axis and i put 3, -2 </p>

<p>i dont know.</p>

<p>you guys are right, its (-2,-3). damn, that was an easy one too..</p>

<p>i really hope i did well. because there were deff. some tough/tricky questions.
and it seems like everyone here did great ha.ha. we shall see in a month!</p>

<p>are you guys going to retake in june? or what are you taking in june?</p>

<p>why couldnt it be (-3,-2)...</p>

<p>it makes more sense than (-2,-3)</p>

<p>physics <---- all memorizing theories, lame</p>

<p>@ goodatlife: if the original point was (2,3) then the reflection would be (-3,-2)</p>

<p>if the original point was (3,2) then the reflection would be (-2,-3)</p>

<p>i just dont remember which is was</p>