<p>I also got 24 for the bakery question but Im assuming I am wrong.</p>
<p>For the allowance, it was 1/4.</p>
<p>He used 1/4 of his original for the book, and then 1/3 of the remaining ( 3/4 ) for the school trip, so 1/3 of 3/4 is 1/4.</p>
<p>And for the bakery, what you guys did was permutation for 24.</p>
<p>That means that, if there are breads A B C and D, you counted ABC to be the same as CBA and BAC and BCA and ACB and CAB…
It was 4 because it only asked for a combination.</p>
<p>ya it was 1/4</p>
<p>yea kneisser i was like that too</p>
<p>No bakery was 4 you had to use combinations</p>
<p>OH YOU’RE KIDDING ME!
It asked for how much 1/3 of 3/4 was?! YEARGH</p>
<p>@ Rustgust ; I see, thanks for explaining!</p>
<p>for the one that was 3/2 the problem was -
Jill ran half of Sam’s distance. Sam ran 3 times Aisha’s distance. ratio jill’s distance to aisha’s. substitute values - Sam 6 Jill 3 Aisha 2
the answer was 3/2</p>
<p>I got a ratio of 2:3?
J = 0.5 S
2J = S
S = 3A
2J = 3A</p>
<p>Can someone explain the rotated square and how the area was 5?</p>
<p>umm you know that the sides of the square will be rad 5, this is because if you were to use the pythagorean theorem, you would have 2 and 1, and the hypotenuse would be the radical of (2 squared plus 1 squared). Therefore, one side is rad 5, just square that to get 5</p>
<p>messy explanation haha</p>
<p>It said each individual small square had an area of 1. That means the length and width was 1. You could find out the side of the big square by using the Pythagorean theorem. Thus, 2^2 + 1^2 = square root of 5.</p>
<p>Knowing that all the smaller squares has side length 1…you could find 2 of the 3 sides of a triangle formed by the rotated square. a^2+b^2=c^2…a=1 b=2
1+4 = 5</p>
<p>There was one complete box in the middle of the square, and on the top, bottom, left, and right there were triangles with 2 base and 1 height.</p>
<p>((2<em>1)/2)</em>4 + 1*1 = 5</p>
<p>I just used the distance formula for that one. I gave each point a coordinate (x,y) from the bottom right of the grid, found one side, and squared it. One side was sqroot(5) so the area is 5.</p>
<p>@coupdefoudre (sp?)
Yeah, so 2J=3A or whatever. Divide by the coefficients: J/A = 3/2
that means the ratio of J:A is equal to the ratio 3:2.</p>
<p>Ah, alright thanks. Didn’t read that each small square had an area of 1… just looked at it and thought I knew how to do it lol.</p>
<p>the answer was definitely 3:2</p>
<p>@ Rust ; I see, thanks, dumb mistakeee. ):</p>