May SAT 2011: Math Section

<p>-n^2 + n</p>

<p>Yeah i’m pretty sure that was the equation, and n was 1.</p>

<p>I put 2, does anyone have a definite answer for this?</p>

<p>@james yeah it was 2, we discussed this pages before.</p>

<p>WOW major fail by me on the n^2-n question. Completely missed the double negative to add 1. Lol serves me right, as I was working through the math I was like wow is this a joke.</p>

<p>EDIT: Oh… now I remember that question! Yeah, I put 2.</p>

<p>Can someone explain why in the question where it has three isosceles triangles sharing a vertice x+y+z = 240? I thought it was 180</p>

<p>The three isosceles traingles had angles 70-70-40. Since the three angles labeled x were 40 degrees. You simply multiplied 3 * 40 which equals 120. Total (360) - 3x Angles (120) = 240 degrees</p>

<p>davidthefat:</p>

<p>2^3 = 8 = V
2^2 = 4 = V</p>

<p>V = 8
A = 4
A^(2/3) = 2.519842099789746329534421214556456701140502929403 0159601639…
A^(3/2) = 8</p>

<p>∴ V ∝ V^(3/2)</p>

<p>There you go</p>

<p>Hum, if I recall correctly from basic middle school math, the surface area of a cube is 6s^2, not s^2. That would be the area of the face. That is a flawed question and they shouldn’t count it.</p>

<p>Can someone jog my memory here…</p>

<p>Was the metals question (17:2), boat question (12 people) and something with like p+ some other letter question a part of the experimental or the real thing?</p>

<p>I think those questions were experimental.</p>

<p>1st post!!!
Ok so I’ve read through all of these pages and there still seems to be disagreement about the question that had the perpindicular lines and the angle Y that was 40 degrees. This is the only question that I can find that I might have missed. I got 30 along with another guy. A lot of people say they got 10, but I don’t see how that is possible, and I think they are talking about a similar question. Another guy got 25. Could this question be experimental? Somebody did a drawing with question details on page 20.</p>

<p>What was the question with the answer 1.33333. I cannot seem to remember it.</p>

<p>^ it was one with a number line that asked which would be between two points or something, all of the answers were in fractions so you should have gotten 4/3. there was a discussion about it a few pages back where someone said the exact question i think.</p>

<p>did anyone get section 2 as their experimental? lol</p>

<p>I think I did. </p>

<p>Does anyone remember the last 3 problems in the NON Experimental section?</p>

<p>@fastnamegender: Exactly! That was what I was thinking about the V and A question. How can the surface area be 2^2? I put A^(2/3) because every value I plugged in (2,3,5, etc.) resulted in A being a bigger number than V, and A^(2/3) is the only choice where A is bigger than V.</p>

<p>

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<p>Even if it was 6*s^2, my logic still stands. 6 is a constant, it is still directly proportional. Its like y = x, and y = 6x. They are both directly proportional because the slope of the line is constant all the way through.</p>

<p>edit: Oh I see the problem, I put the wrong letter… its:</p>

<p>2^3 = 8 = V
2^2 = 4 = V</p>

<p>V = 8
A = 4
A^(2/3) = 2.519842099789746329534421214556456701140502929403 0159601639…
A^(3/2) = 8</p>

<p>∴ V ∝ A^(3/2)</p>

<p>@goose2460 the answer was 10 for the angle x when they gave angle y=40.
i’ll try to explain how i did it:
those two lines were perpendicular so the angle at top with the two smaller angles equaled 90.
so then for the big triangle formed by the two smaller triangles you know two angles, 90 and 40 so the last angle would be 50.
the they tell you two sides of the left triangle are congruent or something like that so know the angles across from the are congruent too, so the other angle is 50 also.
so for the smaller left triangle you now two angles are 50 so the last must be 80.
that 80 degree angle is part of the 90 degree angle made by the perpendicular lines, so you subtract 80 from 90 to get 10, which is the angle you are looking for</p>

<p>sorry if its confusing, try to go along with a picture</p>

<p>wait. was the star question experimental?</p>

<p>Star was easy: it was whatever was given. They are 8 sides I think and given was 24, if you count the sides of the shaded area it was same as the stars’ number of sides.</p>

<p>Star was definitely not experimental.</p>