<p>How do you solve this?</p>
<p>C..........</p>
<p>Well the easiest way is to plug in nubmers if you have enough time....you can do it much faster if you know the common properties of x, x^2 and x^3</p>
<p>What are the common properties?</p>
<p>argh so many to list..i dono if they are called properties but whatever</p>
<p>x^3 is bigger than x if x>1 or 0>x>-1</p>
<p>x^2 is greater than x if x<0 or x>1</p>
<p>x is greater than x^2 if 1>x>0</p>
<p>x is greater than x^3 if 1>x>0 or -1>x</p>
<p>rthere may be mroe but i cant remember...</p>
<p>thanks for your help.</p>
<p>vehement: that really helped</p>
<p>I hope you're all fast asleep, but for future reference:</p>
<p>How 'bout graphing?
For x<0: x=x^3 at x=-1.
For x>=0: x=x^2=x^3 at x=0 and x=1.
So on four intervals:
1. x<-1</p>
<h2>x^3 < x < x^2</h2>
<ol>
<li>-1<x<0
x < x^3 < x^2
-------------</li>
<li>0<x<1
x^3 < x^2 < x
-------------</li>
<li>x<0
x< x^2 < x^3
(C) x^2 < x^3 < x is never true.</li>
</ol>
<p>i am in la..only 9 pm :P</p>
<p>graphing? nice idea! i am really bad at graphing and would prob have taken 45353345 mkin but those good at it, thats really clever...</p>