<p>I am in desperate need of help on this assignment. I am completely stumped and it will tip my grade one way or the other (from C to B, not even from a B to an A). Thank you very much in advance!!!</p>
<p>So, it is a lab that we will be performing and the object is to produce exactly 2.00g of the precipitate product from the following two reactants: zinc sulfate heptahydrate and potassium carbonate. </p>
<p>Thanks so much, I just can't seem to figure this out!</p>
<p>When you combine ZnSO4-7(H20) and K2CO3, you should get ZnCO3 and K2SO4. The K2SO4 is aqueous. The ZnCO3 is insoluble and will produce a precipitate. I'm not sure about the water. </p>
<p>I think you'll get
ZnSO4-7(H20) (aq) + K2CO3 (s) ----> ZnCO3 (s) + K2SO4 (aq) + 7H2O (l)
OR
ZnSO4-7(H20) (aq) + K2CO3 (s) ----> ZnCO3-7(H2O) (s) + K2SO4 (aq)</p>
<p>I'm thinking the second reaction, but I could be wrong. Once you set the balanced equation, just use stoich to find the required masses of reagents.</p>
<p>Alright, you're making 2 grams of ZnCO3. You should be able to go from there with basic stoichiomtry.</p>
<p>thanks guys, but does the hydrate get distributed so that it is part of both the zinc carbonate and potassium sulfate products? If so, how do you know how much goes to each? Thanks again!</p>
<p>I hate to "bump", but this is my last chance...</p>