November 2009 SAT Math (US only)

<p>Anyone know a question about Sue Ted and Ron and 3 chairs?</p>

<p>euclip its 2/3</p>

<p>for the one for sue ted and ron i think its 2/3. not sure though.</p>

<p>oh thanks I listed all the possibilites out so i’m not sure if i counted it right, but turns out i did</p>

<p>what about a question where they give you a Circle in a Square and Area of Circle = 25 Pi and then they ask for the coordinate of u</p>

<p>area = 25pi so a side of square = 10 and using special triangle rule you get 5</p>

<p>how you get ut nadong, i was thinking that ron and ted are together 6/9 times, you know because the only way they cant is if she is in the middle.</p>

<p>Hey tbonus, I think we have the same math sections. I really hope the second to last one was experimental. </p>

<p>What was the answer to this problem? I dont quite remember what they were asking but F(x)= a+b(X-c) was the equation and a, b, and c were the first three answer choices.</p>

<p>odyssey- for that one I put a.</p>

<p>Joker i listed all the possibilities and counted the ones that satisfy the condition</p>

<p>Okay. Thats what I was thinking too since a is the y-intercept…but I think I ended up leaving it blank. Ugh.</p>

<p>Some people have been saying that the math sections were really easy. What kind of curve do you guys predict?</p>

<p><em>still is unsure about grid-in with constant k</em></p>

<p>Joker How did you get 9 in total? There are three chairs so there should be only 2x3x1=6 ways to do everything</p>

<p>Btw, did you get a question where they give you something like the 3rd root of 2x^2 = 2y or something, and you have to find x^3-y^3? That one was number 8 before Grid in so it’s suppose to be hard. I got A) .125</p>

<p>od it was
a+b(x-c)^2
so the answer was a+bc^2</p>

<p>a. ?
b. ?
c. ?
d. a-bc^2
e. a+bc^2</p>

<p>euclip i got 1/8 too.</p>

<p>shizzle- was that the last question? If so, I got 9.</p>

<p>the constant k was like 2x-3y=8 and 6x+ky=12
so u have to set the slopes equal</p>

<p>For the dog question, no one has said 8. There were six possibilities for the dog going to the owner, but on the way back there were only two since it could not go through the same door twice. 6 + 2 = 8.</p>

<p>" od it was
a+b(x-c)^2
so the answer was a+bc^2</p>

<p>a. ?
b. ?
c. ?
d. a-bc^2
e. a+bc^2"</p>

<p>tbonus… if you let x=c that whole term becomes zero, so the minimum value the function can have is a.</p>

<p>sorry i was explaning something to a friend and wrote it wrong, yes it is 3x2x1=6, and since the only way they cant be together is if she is in the middle there are two occasions where that can happen. T,S,R or R,S,T. as you can see 2/3</p>