<p>@ahmed29957</p>
<p>I think it’s momentum because force is equal to impulse (change in momentum) over time.</p>
<p>Force isn’t impulse. Momentum = F x t = impulse.</p>
<p>What? Momentum is conserved too! Both of them are conserved! Oh god don’t tell me I’m wrong :|</p>
<p>did anyone else put 10<T<15 for the temperature question?</p>
<p>Yeah momentum is conserved. We were talking about the problem with unstable force.</p>
<p>@Toonlink. It was T> 20. I plugged in numbers and that’s what I got.</p>
<p>For the Rutherford one, wasn’t it that there was a small positively charged nucleus?</p>
<p>toonlink96, Its 15<t<20. there’s="" a="" way="" of="" solving="" it="" to="" the="" very="" last="" bit.="" if="" you="" can="" get="" ratio="" c(l)="" c(s)="" …="" right="" hand="" side="" looks="" something="" like="" (t-10)="" (20-t)="" was="" given="" that=""> C(s) … so T-10 > 20-T … that give T>15 !</t<20.></p>
<p>For the rutherford one, yes. it was a “small, massive, positively charged nucleus”. No idea why they put Small and massive there. Maybe it meant small and massively charged or something. The other options were vague so that one has got to be it.</p>
<p>@ahmed, why are you using T -10 and 20-T? Shouldn’t it be T-10 and T-20? The final temperatures werent given for either. That would give you T>20.</p>
<p>I said impulse over time haha</p>
<p>T-10, because the temperature of the solid will obviously increase, since its mixing with a hotter liquid. 20-T because, the temperature of the liquid will decrease( again, obviously) because it’s mixing with a cooler solid! No heat is lost to the surroundings.</p>
<p>What did you guys get for the last question? Also, the red sun at sunset ( is that polarization or interference?)</p>
<p>EDIT : Had no idea what scattering was. =(</p>
<p>Red sunset is Scattering.</p>
<p>i put scattering for that one…</p>
<p>@ahmed, that is correct but in the formula Q= mc(delta T), delta T is defined as Tf - Ti so regardless of whether the temperature decreases or increases, Tf should come first. The negative sign of the delta T will tell you that it decreased — no need to swap Ti and Tf. That was my thought…not sure though.</p>
<p>was lenz’s law the one demonstrated by the graph??</p>
<p>@toonlink96 wasn’t it ohm’s law</p>
<p>woooo 500…</p>
<p>That is true, when you have numeric values. If you solve algebraically you need to subtract smaller value from larger value. </p>
<p>An alternative method is by applying some logic. It’s given that the specific heat capacity is larger for the liquid. That means that the final temperature is going to hover around closer to the temperature of the liquid because it needs more heat to raise its temperature. One way of looking at it is that it would hold on to its heat…(weird)</p>