<p>calculating the force on a particle question on the physics</p>
<p>Here is the answer: <a href=“https://www.■■■■■■■■.com/questions/370?title=SAT+Physics+II+Question[/url]”>https://www.■■■■■■■■.com/questions/370?title=SAT+Physics+II+Question</a></p>
<p>The problem said that the diagrams were proposed outcomes of the collision, not actual outcomes. So they could have broken the law of conservation of momentum.</p>
<p>I still think momentum is conserved for I, II and III. When you add the momentums of the two objects in III, it shows up as 2.</p>
<p>Rutherfords model for the atom question, answer here:
<a href=“https://www.■■■■■■■■.com/questions/372?title=Sat+2+Physics+Question[/url]”>https://www.■■■■■■■■.com/questions/372?title=Sat+2+Physics+Question</a></p>
<p>question regarding the constant magnitude of force
<a href=“https://www.■■■■■■■■.com/questions/371?title=SAT+2+physics+question[/url]”>https://www.■■■■■■■■.com/questions/371?title=SAT+2+physics+question</a></p>
<p>I think case III had one ball at 45 degrees and the other at -90 degree, both at sqrt2 magnitude? So tthat results in momentum along the y-axis of sqrt2 - 1, which is not 0 as it was before the collision.</p>
<p>
Momentum is a VECTOR, not a scalar, so you cannot just “add the momentums” of the two objects if they are not both moving along the same coordinate axis. Although I separated it out into x and y, you could achieve the same result by finding the resultant momentum vector, √(Px^2+Py^2)</p>
<p>What would be the curve for this test ?</p>
<p>For the rough patch one, when the kinetic energy was decreased from 36 J to 9 J (calculated somehow), the object would travel a fourth of the given distance (2 m). So put 0.5 m. Also, there was one question in which momentum always changes with a constant acceleration. I figured, in linear motion velocity could increase and in circular motion velocity changes direction and since momentum gets its direction from velocity, it too would change. The mechanics on this test was much more difficult than what I practiced for. Also, I put that electrons interfere. I watched a youtube video: Dr Quantum - Double Slit Experiment. At around 1:58 he starts talking about electrons. I’m really hoping for a generous curve.</p>
<p>I’m interested to know what the curve is predicted to be too. -12 raw for 800? Or is that too lenient/harsh? I can’t tell, seeing as all the practice tests I took were much easier than the real thing, even the CollegeBoard released exam.</p>
<p>So the CB book says -16 raw for 800, Princeton Review says -15 raw, and Kaplan says -12. I also saw someone comment that this test was harder than October, which my friend said had a fairly easier than normal curve. So is about -16 right then? More? Less?</p>
<p>I feel like this was a -14 raw (=800) kind of test. I took this two years ago and I could actually do the mechanics questions then. Typically I don’t like electricity and magnetism, but I feel like more questions had to do with right hand rules (the part that I understand). PR gives a -15 raw curve, but I don’t know if that’s quite accurate. I heard that PR is easier than the actual exam.</p>
<p>Actually it was 18J not 9J. You can calculate by using the formula —</p>
<p>0 = Vo^2 + 2ax
Vo = 3 as calculated from the given 36J.
0 = 9 + 2a (2)
a = -9/4
Mass was 8 kg. Use F = ma. F = 8(-9/4) = -18.</p>
<p>I don’t remember the question. Did the mass change? I remember using conservation of energy.</p>
<p>question about collisions dealing with kinetic energy,momentum: heres the answer,</p>
<p><a href=“https://www.■■■■■■■■.com/questions/369?title=Physics+SAT+II+Question[/url]”>https://www.■■■■■■■■.com/questions/369?title=Physics+SAT+II+Question</a></p>
<p>There was one about the proton and a positive plate… what statement was incorrect? Answer choices: force on the plate, force on the proton, KE is 0, v is 0, or PE is lowest.</p>
<p>I think I put PE is lowest. It’s definitely not KE is 0 or v is 0 cuz it said the proton was stopped. and I don’t think it’s the first two either because both have to be true or both have to be false by newton’s third law?</p>
<p>PE was at the maximum (all kinetic energy turned to potential energy), so PE as the lowest was the correct choice for the question. The other choices don’t make sense. If the proton stopped, velocity is 0, thus KE is 0. And the force on the plate equals the force on the proton, (coulomb’s law: F = kq1q2/r^2 the order of multiplying the charges doesn’t matter).</p>
<p>I’m so screwed for this test…</p>
<p>@zma11rocks, same. If I don’t get at least a 730, I wasted my time studying for this thing. I’ll probably just end up sending my BioM score from freshman year anyways.</p>
<p>I chose potential energy is minimum too!</p>