<p>Did you get 2 for that z= series of equations?</p>
<p>also I read that you guys got 900 for the 4 digit number problem... if I can remember properly the first digit was 1, and the rest could only be POSITIVE integers and the digits couldn't repeat. So how is it not:</p>
<p>9 (the second digit has 8 options... 2, 3, 4, 5, 6, 7, 8, or 9) x 8 (the next digit has 7 options as it can't repeat the preceding digit) x 6 (once again the digit can't repeat the preceding digit) = 336? How did you get 900?</p>
<p>indeed you were! i am positive this time, because i couldnt get it at first (im a idiot, i thought 10 was a integer so i was multiplying by 11, not 10) and i was like *** so i reread it like 5 times to see if digits couldnt repeat. the only question i read carefully!</p>
<p>We understand the question and how to solve. The only problem is whether or not the digits could repeat. It's painfully (literally) obvious to us why we were wrong >_></p>
<p>so you're saying the question noted that the 1 couldn't repeat but the other digits could? i'm confused... because if that's the case then it would be 1 x 9 x 9 x 9.</p>