<p>yup 7 was the answer.</p>
<p>radeon, it was 12. i don’t remember what I put but I’m assuming I got it wrong.</p>
<p>That’s because a triangle’s area is .5(height x base), so (.5 x (sqrt (5^2 - (6/2)^2) x 6) = 12</p>
<p>^ Perhaps, but the answer was 12. Divide the isosceles down the middle, and you get 2 3-4-5 triangles. Areas of 6, total is 12.</p>
<p>does anyone who actually knows definitively how to do the 1/180 vs 1/56 one wanna explain?</p>
<p>yeah I’m aware the answer is 12, but I may have divided too many times by accident. was 6 an answer choice?</p>
<p>I got like 1000 something for that one using dimensional analysis.</p>
<p>(1 week x 5 days/week) x 180 days/year. Each of them were 250-300ish and you got an answer of 1040 or something.</p>
<p>6 might have been A or something. I think B was like 12 and one of them was 24. Then again, I’m not completely sure.</p>
<p>for the 1/180 vs 1/54 one:</p>
<p>you needed a sum of 17 or 18 when you rolled the dice three times
so the total number of combinations is 6<em>6</em>6= 216
the only possible sum for 18 is: 6 6 6
the possible sums for 17 are:
5 6 6
6 6 5
6 5 6</p>
<p>so thats only 4 so you divide 4/216= 1/54</p>
<p>@Flotsam: I’m not sure but here was my method for 1/54.
Ways to get 17/18:
566
656
665
666
Out of 6^3 total possibilities (216?).
4/216 reduces to 1/54.</p>
<p>Again, I was totally unsure about this question, but this was just my way!</p>
<p>sry, jet, but the answer was x over root3 b/c the rise was root3 and the run was 1. root three is oppsossite of the 60.</p>
<p>the 20 min question with the graph was f(v) - f(s) or something right? It had to be the y value of a max minus the y value of a minimum. ??</p>
<p>^I think it was f(v) - f(t), not f(s).</p>
<p>Yea I remember that one. And talking about graphs, there was one with four places where the absolute value of the function was 1.</p>
<p>@coupdefoudre, thanks, im really not sure either (i got 1/108) but it seemed to make sense to me at the last second before the proctor told us time was up so i impulsively filled in. pretty sure im up to 2, maybe 3 wrong not to mention the dumbest mistake iv ever made with the 25 books $65 question. oh well.</p>
<p>Combination, not permutation.</p>
<p>There are (6<em>6</em>6)/(3<em>2</em>1) possibilities for different sums.</p>
<p>Two possibilities (three six’s), (two six’s and a five) that the sum is 17 or 18.</p>
<p>1/18. I’m sure.</p>
<p>(But if I’m wrong, FUUUUUUUUUUUU. That is all.)</p>
<p>anyone have the password question? or was it experimental?</p>
<p>@ boston u member the answer choice? It had to a maximum minus a minimum or what?</p>
<p>I had a question that was like 2(a+b) + c = 38 and 2(b+c) +a =40 and so on…idk remember the exact problem but it asked for the perimeter…i had no clue so i just took the end values, added it up and divided by 3 to get 40…can anyone explain this one???</p>
<p>Can someone give me an example of the supposed “exp” section/questions?</p>
<p>I think I got one…but I’m not sure.</p>
<p>Do you remember if that was E?
(For the max/min).</p>
<p>@ Mike your right got same thing 100% sure everyone is not taking into account order.</p>
<p>@coup - yes</p>