<p>I had 4 math sections with only one grid-in</p>
<p>This is my recollection of the dice problem. There are three dice rolled simultaneously and what is the probability that you either roll a 17 or 18.</p>
<p>The link in the above post does settle the issue for me, the probability of rolling 18 is 1/216, there is no disputing that, the dispute is what is the probability of rolling 17, and here is where I went wrong because there is more than one way to roll a 17, there are 3 ways to roll 17, so 1/216 + 3/216 gives you 1/54</p>
<p>I had 4 math sections with two grid-ins. Was the paperbag/hardcover one an experimental section?</p>
<p>so the one where x^-y=1/8 and y^z=243 and it asked for X+Z was experimental??</p>
<p>Anyone know what the experimental was?</p>
<p>what do you guys think -1 and -2 will be</p>
<p>That’s how I got the dice problem too. 1/54. 1 way to get 18, 3 ways to get 17.</p>
<p>I think the experimental for math is the one with the combinations of 2 rooms occupied with windows and 3 w/o windowns. There was also an inverse question before that. Was the section with the obtuse triangle on the experimental?</p>
<p>obtuse triangle?
the one where it asked for the third side?</p>
<p>Okay, then the windows was experimental. And nope, I had the obtuse triangle and not the windows.</p>
<p>@Attack Pack, no that section wasn’t experimental and the answer was 7.</p>
<p>^yea…</p>
<p>Damn, are you sure though?</p>
<p>Which obtuse triangle problem is this??? I don’t seem to remember doing that one…</p>
<p>So the question with the paperbag and hardcover was experimental?</p>
<p>@Rennir: If angle x > 90 degrees, and two sides are 6 and 8, what is a possible value for the third side? (Grid in).</p>
<p>what was the answer to the third side of the obtuse triangle. LOL, I completely messed up on the locker question and blindly guessed 290, I think I got it right. And for the dice thing i got 1/54 too. It’s too illogical to be 1/18 right?</p>
<p>No the paperback and hardcover section with the boys hall lockers, was not experimental. I only had three sections of Math and I had that section…</p>
<p>In the dice problem, it doesn’t really matter if it is one die or not. Just think that there are three rolls. There are four possible outcomes to the roles that would give you 17 or 18:</p>
<p>6, 6, 6
6, 6, 5
6, 5, 6
5, 6, 6</p>
<p>There are 216 outcomes from the three rolls: 6 * 6 * 6.</p>
<p>Each of the four desirable outcomes would then each have a chance of 1/216. Adding them together would then be: 4/216, which simplifies to 1/54.</p>
<p>For those of you crying that “order doesn’t matter!” You are completely right. But my explanation totally proves that. If order doesn’t matter, then the three dice would mean that there are three equal chances for the five to appear on any one of them.</p>
<p>For those of you thinking of separate single die rolls: Most people seem to be missing this because they are thinking “If the first two are sixes already, then the third dice HAS to be a five to fit the criteria,” but why aren’t you thinking, “If the first is a five, and the second is a six, then the third one MUST be a six to fit the criteria” or “If the first is a six, and the second is a five, then the third MUST be a six…”</p>
<p>@theRADtomato47</p>
<p>You BLINDLY guess 290? Well, lucky you.
I also got 1/54 for the dice question:
The chance of getting 18 is 1/216.
The chance of getting 17 is 3/216.
Thus, the answer is 1/54.</p>