October 2010 Math SAT Thread

Test Preparation SAT Preparation
781

<p>I am pretty sure the top row had 4 large computers and 2 small ones on top of one another. Each large computer was a 1000 (as far as I remember). 2 small computers on top of one another is 2*500=1000 for those small computers. Top month is 4000+1000=5000 :slight_smile: but who knows . . . we ll see who is right or wrong when scores come out.</p>

<p>P.S. as to the dice, the question is not ambiguous at all. Number of total possible combinations is 6<em>6</em>6 =216. Thus, the probability for a given 3 dice combination (in which, using layman’s language, order matters) is 1/216.
The only ways to get 18 is 6+6+6 - thats 1/216
Ways to get 17 are 5+6+6, 6+6+5, 6+5+6 - total of 3 distinctly ordered combinations, each with probability of 1/216.</p>

<p>Answer is 1<em>(1/216) + 3</em>(1/216) = 1/54</p>

782

<p>Yaha I am completely confident that you pulled those images out of your ass.</p>

<p>I also have great memory. So trust me, there were four computers and NOT 5. I also glanced at that problem twice. So it’s ingrained pretty hard into my brain.</p>

783

<p>There were 5 big computers and each was equal to 2000 and the smallest was 2 comupters which was equal to 4000. 10000-4000=6000</p>

784

<p>I don’t even remember little computers in the top month.</p>

<p>@pkm2232; so the z=5 was just your knowledge?
ughh I should have tried different roots of 243
 I tried to do systems of equations and logs.</p>

<p>YAHA: I put 1/180, but it makes sense on reflection that its 1/54. If you think about it, shouldn’t it be easier to get one five on one of the dice than to get straight sixes? Since there can be different orders for the 665, and only one possible order for the 666. Therefore since its easier to get 17 than 18, there should be a higher probability to get 17 than 18. This thinking confirms the 1/54 theory.</p>

<p>Not saying I don’t wish 1/180 was right D:</p>

785

<p>there were not 5 big computers.</p>

<p>It was 4 big and 1 small. I guarantee you. But you can have your VERBAL victoy if you like and i’ll keep the points to the right answer :)</p>

786

<p>^or you are just wrong</p>

787

<p>^we’ll see</p>

788

<p>on the list where it says “PR = 4 rad 2”</p>

<p>Its supposed to be 8root2 right?</p>

789

<p>@linger
yeah</p>

790

<p>Does anyone remember getting 36 for something that is not possible? It was choice A
</p>

791

<p>^ I remember getting 20 for something that wasn’t possible and it was choice E. Maybe that was my experimental though.</p>

792

<p>The dice probability question was tricky, thanks for the explanation YAHA.</p>

793

<p>the length of pr is 8 rad(2), the radius was 4 and you connect it with the other radisu and make a 45-45-90 triangle where the legs are 8 each.</p>

<p>tell me if i said something wrong</p>

794

<p>@ papapia - could you explain? I now feel like I remember writing 4500.</p>

795

<p>If it helps the choices were A. 36, B. 18, C. 4, D. 2, E. 1 or something along those lines
</p>

796

<p>^ 1.
aaaaaaaa</p>

797

<p>Does anyone remember the problem with the bacteria and time? It was a graph and I believe it was #3 in a section? Also, what is the cylinder one with 64?</p>

798

<p>

How was the answer 1?? I think it gave you 0<x<y<6 and asked you which number was not possible for x*y. Isn’t 36 also not possible?</p>

799

<p>Yeah the answer was 1. It asked which was not possible for the abs value of XY.</p>

800

<p>yea, but how is 36 possible?</p>