<p>Debate_addict, brilliant solution for the problem. I used law of sins since I didn't want to waste time trying to find the "clever" method, but that's a very elegant solution.</p>
<p>okay then the section with RST = experimental if eloquence did not, indeed, have that section.</p>
<p>Moving on...did any of you get the question that had x/4 for the base of the triangle and asked how many you needed to form a square? I put 8</p>
<p>the RST (whatever that rst is) is experimental- i didnt have it too
duper: thanks..if you know that sin rule is SAT II material, then there HAS to be another way of finding it..though sin rule is relatively fast as well..</p>
<p>I'm relieved now -- I got stuck and ended up putting 40.</p>
<p>for the question where you had to find the area of the shaded region in the quadrilateral it was 50 right?</p>
<p>2 wrong, 1 omit = ?</p>
<p>
[quote]
My free response:
1/5
1.25
145
4
256
4000
6
2
63
13.5
[/quote]
</p>
<p>mine were:</p>
<p>1/5
1.25
145
4
256
4000
12
2
63
36</p>
<p>does anyone know who is correct?</p>
<p>moldoll - i got 50 also for shaded area</p>
<p>it was (14 * 7) - (8*6) = 50...</p>
<p>and the last one was definitely 13.5...the solutions to the quadratic were 1.5 and 3, and the result of x = o was 9, so it is 9*1.5 = 13.5</p>
<p>"the question that had x/4 for the base of the triangle and asked how many you needed to form a square?"
answer was 8</p>
<p>"for the question where you had to find the area of the shaded region in the quadrilateral it was 50 right?"
50 because area of the whole thing was 98 and the area of both triangles together was 48.</p>
<p>what did u guys get for the 4 digit number one, the 1st digit has to be 2, and the last digit can not be 0, how many different numbers can make the 4 digit positive, or something like that??????</p>
<p>you guys sure the bead one was 76?</p>
<p>i put 74 and i was pretty sure when i did it, i think i even checked it over.</p>
<p>900</p>
<p>10 x 10 x 9</p>
<p>900 10 chars</p>
<p>and it was def 76. sorry 74 woulda been red</p>
<p>it was how many possibilites exist for a 4 digit number where the first digit is 2 and the last is not 0 i put 900</p>
<p>oh and is there a mistake on one of the math problem, it was like T is all even integer, S is the set of number divisible by 7, what's not in T and S??? both A and B don't work. what's the answer?</p>
<p>Alej, the bead one was 76 if I rremember correctly.</p>
<p>***, were we supposed to round on the cylinder/cone question?! 'Cause I got a decimal..</p>
<p>yeah, it was 76.</p>
<p>so, what were the grid in answers?</p>
<p>and, concrete jungle, i am pretty sure it should have been exactly two inches. thats what i got.</p>
<p>oh good, I put 900 too.</p>
<p>the bead is 76</p>