<p>hey guys!
it has been 48 hrs. collegeboard has posted the frq questions here <a href="http://apcentral.collegeboard.com/apc/public/repository/ap08_calculus_bc_frq.pdf%5B/url%5D">http://apcentral.collegeboard.com/apc/public/repository/ap08_calculus_bc_frq.pdf</a> ...let the discussions begin?</p>
<p>first of all? wut did ppl put for 1d?</p>
<p>for 1d, I did:</p>
<p>the INTERGRAL from ZERO to TWO of ((sin(pi x) - (x^3) + 4x) * (3-x)), dx</p>
<p>I don't have my calculator, but was the answer something around 9.something?</p>
<h1>2c you guys get 2?</h1>
<h1>4(a) - t = 3 because thats the time when the particle stops and reverses direction; the area under the curve is greatest here</h1>
<h1>4(b) - 1 value of t; the total area under the curve equals -8 only once, and that is when t = 3; the object goes to x = -8 when t = 3, goes to x = -5 when t = 5, and gets to x = -7 when t = 6</h1>
<h1>4(c) - speed is decreasing because the velocity is approaching zero</h1>
<h1>4(d) - [0,1) and (4,6] - the velocity of the particle begins to slope downwards, implying negative acceleration</h1>
<h1>4 was the ONLY ONE THAT I DID GOOD ON LMFAO i sucked at everything else</h1>
<p>and for the very last one, 5(c), i used the Stand and Deliver tic tac toe method, not the uv-vdu method. Do the readers not award points if I do this?</p>
<p>tag thread :)!</p>
<p>ftc123...wow i got different answers than you (i think..maybe i just dont understand what you're writing)...ISHT!</p>
<p>4(b) is 3 Remember initial condition is -2 so at three it is at -10.</p>
<p>2(c) is also three. Draw a graph</p>
<p>Others are right.</p>
<p>I got the same answers as stix :D</p>
<p>I think I <em>might</em> have gotten 4c wrong for some reason..dont remember what i put...</p>
<p>1(a). 4
b. expression
c. 9.987 (or something like that)
d. 8. something</p>
<p>2.8 people per hour
b.155.25 (ish)
c.3
d.973</p>
<p>3.62.7 ish Less than
b.62.9 ish<br>
c. 2.703 or whatever *10^(-4)</p>
<p>4.t=3 and position -10
b. 3
c. decreasing
d. (0,1) (4,6)</p>
<p>5.minimum
b. (2,3)
c. 7+3e-e^3</p>
<p>6.graph
b.105/16
c. 7.25
d. (6,8]</p>
<p>Some Rounding issues but whatever</p>
<p>yeah stix is right :( that blows there goes my frq</p>
<p>Argh I only put one for 2(c) :/</p>
<p>I thought that for 5(b) there was no interval where f''(x) > 0 and where f'(x) < 0?</p>
<p>Ahhhhhhhh nooooo I don't want to remember that exam!</p>
<p>I got (2,3) for 5b as well, so I'm pretty sure it's right.</p>
<p>Lol, I completely BS'd 3c and got it right (according to stix's answers). :D</p>
<p>I recognize a lot of those answers, so.. yay! ^_^</p>
<p>sigh, there goes my chances for a 5. Now I'll have to retake if I want credit :'(</p>
<p>Yeah, just retake it next year. I took AB as a class and studied the BC material every night or so in the 2-3 weeks before the exam, and I'm very confident that I got a 5. I also did the 2003, 2000, 1998, 1997, and 2008 audit BC multiple choice in addition to maybe 25-30 free response questions. After doing all of that there was very little I hadn't actually seen, so the test was a breeze. :)</p>
<p>I'm certain I would have gotten a five on AB, but I decided to chance BC. Bad idea it seems now, there were a lot of series in there that I didn't know how to do :/</p>
<p>Oh well, a 4 is still good for admissions right (homeschooled)? And I'll retake next year for the credit.</p>
<p>I believe so, yes. A 4 is enough to grant credit at many colleges too, so that's a plus :)</p>
<p>I got answers similar to stix's and also got
(2,3) because it was (-oo,3) u (2,oo)</p>
<p>For the range one on the logistic curve, I put (6,8) but I also whimped out and put (0,6) and I said something about if the points on the solution are above y=6 then it is (6,8), but if they're below it is (0,6). Is this incorrect?</p>
<p>^5b has to be never....how is it 2,3...f'(x)<0 and f''(x)>0, are never met simaltaneousy in any one given interval so....</p>
<p>I can be wrong, but when I did my inequalities I got that one was met for (-oo,3) and the other from (2,oo) and the cross section of that is (2,3)</p>